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# ∫tan x

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1. ∫tan x =

∫(sin x/cos x)

Sin x/cos x is of the form f'(x)/f(x)

therefore the ∫sin x/cos x = -ln|cos x| + c

However, my book also states that the ∫tan x = ln|sec x| +c ?
2. (Original post by sabre2th1)
∫tan x =

∫(sin x/cos x)

Sin x/cos x is of the form f'(x)/f(x)

therefore the ∫sin x/cos x = -ln|cos x| + c

However, my book also states that the ∫tan x = ln|sec x| +c ?
How can you rewrite this?
3. (Original post by sabre2th1)
∫tan x =

∫(sin x/cos x)

Sin x/cos x is of the form f'(x)/f(x)

therefore the ∫sin x/cos x = -ln|cos x| + c

However, my book also states that the ∫tan x = ln|sec x| +c ?
Remember that,
-ln(a)=ln(1/a)
4. (Original post by cpdavis)
How can you rewrite this?

(Original post by Blutooth)
Remember that,
-ln(a)=ln(1/a)
Just as you wrote this, I remembered ! Thanks

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