CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
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CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
This is Section A, obviously loads/most are wrong because I thought this was a ridiculously hard exam, and a lot of it unrelated. I still don’t think boundaries will change too much because AQA aren’t like that, 70 for an A i reckon. Everyone edit and let’s try and come up with a proper mark scheme
Question 1 is 9 marks
1a) Why is Phosporous Oxide stored in water? – Reacts violently in air
b) Why P4O10 not P2O5? – P4O10 is it in its most stable form under standard conditions
c) Equation = P4O10 + 6H2O = 4H3PO4
pH = 0
d) equation for MgO + H3PO4 – No idea
e)Why can you use excess MgO? Because H3PO4 is a strong acid
f) Why is NaOH an environmental risk? Strong alkaline harms fish?
Question 2 is 7 marks
2a) Equation – G = H – TS
b)Gradient = 0.1 Units = J K mol-1 Symbol = S
c) Why is significance of temperatures below the temp line – delta G is negative so reactions are feasible
d) Why does curve slope? – Change of state, freezing.
Question 3 is 10 marks
3a) delta H =
b)Delta S =
c) T = 700 K? Can’t remember the other 2 but they gave this temperature.
d) why would NO2 not form? – Not 700K
e) N2 + O2 = NO2
f) same number of moles so small entropy so small TdeltaS
Question 4 is 12 marks
4a) Define enthalpy of electron affinity – Enthalpy change when 1 mole of electrons added to an isolated atom in the gas phase
b) Why is F- more electronegative – more shells so more and further from nucleus
c) Why does F- have more negative enthalpy of hydration? No idea
d) Calculation – can’t remember I got 900 something I think
e) Why is it always feasible – delta G always negative because entropy positive and enthalpy change is negative?
f) Can’t remember but it was 2 marks
Question 5 (a disgrace) was 17 marks
5a) Weakest oxidising agent – CdO(OH) because it was most negative.
b) emf = 1.1? can’t remember
c) Equation – cant remember
d) Carbon anode – conduct electricity
e) Essential property of porous cover? – Inert
f) Why leakage? Ions used up
g) +3 and reverse equation
h) Environmental problem? More waste/to landfill
Two ethanol (wtf) fuel cell questions
I) Carbon neutral as no net emission into atmosphere as ethanol comes from plants that photosynthesise.
Question 6 was 10 marks
6a) Coordinate bond
b) O atom acts as Lewis base and donates electrons
Metal ion acts as Lewis Acid and accepts electrons.
c) 180 degrees
d) ratio 3:5 and calculation – no idea
Someone else do section B?? -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
my thoughts only, may be wrong...
i thought 2d was condensing o.o but any change in state would give a diff gradient though right?
4c Cl- has more shells than F-, just saying, so F- attracts e- more so more electronegative
5c i said greater charge density so polarises water more, not sure if right
4a did you have to say one atom or one mol? q was kinda badly worded and 1 mol electron is kinda too much for one isolated atom lol
5b emf i got .23V, as cell emf was 1V but half cell emf was 1.23V, so 1.23-X=1, X=0.23
5f i got zinc cathode is sacrificed as it is oxidised to zn ions so thickness of zn coating reduced
6d final answer 96.3 or over 100 if used given ratio
5e can you also say allows ions to pass between solutions?
glad to know it was CdO(OH) for 5a :3
oh and thx for this :3Last edited by Yosemite80; 19-06-2012 at 20:11. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
one of dH or dS was 70.5 but forgot sign... might have been negative
2b units 0.1kJmol^-1K^-1 or 100JK^-1mol^-1, as the axes were in kJmol^-1
my guess for 1d is 3MgO+2H3PO4->Mg3(PO4)2+3H2O, only one which made some sense...
3e is 2NO, they asked for nitrogen monoxide i thinkLast edited by Yosemite80; 19-06-2012 at 20:30. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark SchemeHave you got the QP if so I will do one if you like.(Original post by TheBigDog)
This is Section A, obviously loads/most are wrong because I thought this was a ridiculously hard exam, and a lot of it unrelated. I still don’t think boundaries will change too much because AQA aren’t like that, 70 for an A i reckon. Everyone edit and let’s try and come up with a proper mark scheme
Question 1 is 9 marks
1a) Why is Phosporous Oxide stored in water? – Reacts violently in air
b) Why P4O10 not P2O5? – P4O10 is it in its most stable form under standard conditions
c) Equation = P4O10 + 6H2O = 4H3PO4
pH = 0
d) equation for MgO + H3PO4 – No idea
e)Why can you use excess MgO? Because H3PO4 is a strong acid
f) Why is NaOH an environmental risk? Strong alkaline harms fish?
Question 2 is 7 marks
2a) Equation – G = H – TS
b)Gradient = 0.1 Units = J K mol-1 Symbol = S
c) Why is significance of temperatures below the temp line – delta G is negative so reactions are feasible
d) Why does curve slope? – Change of state, freezing.
Question 3 is 10 marks
3a) delta H =
b)Delta S =
c) T = 700 K? Can’t remember the other 2 but they gave this temperature.
d) why would NO2 not form? – Not 700K
e) N2 + O2 = NO2
f) same number of moles so small entropy so small TdeltaS
Question 4 is 12 marks
4a) Define enthalpy of electron affinity – Enthalpy change when 1 mole of electrons added to an isolated atom in the gas phase
b) Why is F- more electronegative – more shells so more and further from nucleus
c) Why does F- have more negative enthalpy of hydration? No idea
d) Calculation – can’t remember I got 900 something I think
e) Why is it always feasible – delta G always negative because entropy positive and enthalpy change is negative?
f) Can’t remember but it was 2 marks
Question 5 (a disgrace) was 17 marks
5a) Weakest oxidising agent – CdO(OH) because it was most negative.
b) emf = 1.1? can’t remember
c) Equation – cant remember
d) Carbon anode – conduct electricity
e) Essential property of porous cover? – Inert
f) Why leakage? Ions used up
g) +3 and reverse equation
h) Environmental problem? More waste/to landfill
Two ethanol (wtf) fuel cell questions
I) Carbon neutral as no net emission into atmosphere as ethanol comes from plants that photosynthesise.
Question 6 was 10 marks
6a) Coordinate bond
b) O atom acts as Lewis base and donates electrons
Metal ion acts as Lewis Acid and accepts electrons.
c) 180 degrees
d) ratio 3:5 and calculation – no idea
Someone else do section B?? -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
Section B
7(a)Cr2O72- + 3Zn = Cr3+ + 7H2O + 3Zn2+
2Cr 3+ + Zn = 2Cr2+ + Zn2+
Orange = Green = Blue (5 Marks)
7(b) [Cr(H2O)6]3+ + 3OH- = [Cr(H2O)3(OH)3]+ 3H2O +
Green solution = grey-green ppt
[Cr(H2O)3(OH)3] + OH- = [Cr(H2O)2(OH)4]- + H2O
Grey-green ppt = green solution (4 marks)
7(c) Ligand subsitution
Different ligand makes energy gap between d orbitals different so electrons require more/less energy light from visible spectrum to excite??
7(d) overall reaction has a postive +1.67V EMF
CrCO3
[Cr(H2O)3(OH)3]
Cr3+ more highly charged pulls electron density from coordinate bonds more, weakening OH bond in H2O making it more susceptible to hydrolysis/deprotonation and more acidic. Therefore it is acidic enough to react with the carbonate ion to release carbon dioxide but the Cr2+ is not so the metal carbonate is formed. (7 marks)
8(a) (12 marks)
8(b) 2SO32- + O2 = 2SO42-
4CO2+ +4H+ + O2 = 4CO3+ + 2H2O
2CO3+ + H2O + SO32- = 2CO2+ + SO42- + 2H+
Faster with CO2+ as in same phase and oppositely charged so collison more likely (4 marks)Last edited by MissMarple1911; 19-06-2012 at 20:32. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark SchemeThanks for starting one of these!(Original post by TheBigDog)
x
For 1d): 3MgO + 2H₃PO₄ → Mg₃(PO₄)₂ + 3H₂O (treated it like a normal acid-base reaction?)
For 1e): Excess MgO can be used because it's not very soluble in water, so the excess won't dissociate and dangerously lower the pH of the lake.
EDIT: Remembered what I put for those awful ethanol fuel-cell questions (can't remember the question numbers though):
Overall reaction: C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
Reaction at ethanol electrode (anode): C₂H₅OH + 3H₂O → 2CO₂ + 12H⁺ + 12e⁻Last edited by Kidneyjean; 19-06-2012 at 20:56. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
1)d) Mg3(PO4)2 + 3H2O
e) Dissociated weakly, pH approx 8, therefore not far from neutral.
2)b) kJ mol-1 K-1 (if you got 0.1, that is)
d) Liquid, not solid? (was going from a gas initially)
c) 794K
d) High activation energy?
e) 2NO, not NO2
4)b) F- has fewer electron shells, less shielding, therefore greater tendency to attract electrons in a covalent bond.
c) Attracts a greater number of delta+ H in the H2O, hence more exothermic.
5)a) Cd (s) The electrons were on the CdO...whatever side, so has to be the solid.
e) Allows the flow on ions (salt bridge).
Those are my few contributions.
If someone posts up the Section B questions, I'll be happy to give remembering those a go too. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
1)d) Mg3(PO4)2 + 3H2O
e) Dissociated weakly, pH approx 8, therefore not far from neutral.
2)b) kJ mol-1 K-1 (if you got 0.1, that is)
d) Liquid, not solid? (was going from a gas initially)
c) 794K
d) High activation energy?
e) 2NO, not NO2
4)b) F- has fewer electron shells, less shielding, therefore greater tendency to attract electrons in a covalent bond.
c) Attracts a greater number of delta+ H in the H2O, hence more exothermic.
5)a) Cd (s) The electrons were on the CdO...whatever side, so has to be the solid.
e) Allows the flow on ions (salt bridge).
Those are my few contributions.
If someone posts up the Section B questions, I'll be happy to give remembering those a go too. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Schemedoesnt Cr dissolve in xs OH-, so would go to Cr(OH)6^3-?(Original post by MissMarple1911)
Section B
7(a)Cr2O72- + 3Zn = Cr3+ + 7H2O + 3Zn2+
2Cr 3+ + Zn = 2Cr2+ + Zn2+
Orange = Green = Blue (5 Marks)
7(b) [Cr(H2O)6]3+ + 3OH- = [Cr(H2O)3(OH)3]+ 3H2O +
Green solution = grey-green ppt
[Cr(H2O)3(OH)3] + OH- = [Cr(H2O)2(OH)4]- + H2O
Grey-green ppt = green solution (4 marks)
7(c) Ligand subsitution
Different ligand makes energy gap between d orbitals different so electrons require more/less energy light from visible spectrum to excite??
7(d) overall reaction has a postive +1.67V EMF
CrCO3
[Cr(H2O)3(OH)3]
Cr3+ more highly charged pulls electron density from coordinate bonds more, weakening OH bond in H2O making it more susceptible to hydrolysis/deprotonation and more acidic. Therefore it is acidic enough to react with the carbonate ion to release carbon dioxide but the Cr2+ is not so the metal carbonate is formed. (7 marks)
8(a) (12 marks)
8(b) 2SO32- + O2 = 2SO42-
4CO2+ +4H+ + O2 = 4CO3+ + 2H2O
2CO3+ + H2O + SO32- = 2CO2+ + SO42- + 2H+
Faster with CO2+ as in same phase and oppositely charged so collison more likely (4 marks)
going by this MS i think i got about 80/100 :/Last edited by Yosemite80; 19-06-2012 at 20:55. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Scheme
the Zinc EMF value was the most negative not the Cd one.. so the mots weakest oxidising agent was the most powerfull reducing agent which was Zn (s)... I think anyways
Why would answer to pouros material be inert ? its stated in the question its non reactive, so we would just be repeating question. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark SchemeI could be wrong but I said that it can't conduct electricity(Original post by Polioz)
the Zinc EMF value was the most negative not the Cd one.. so the mots weakest oxidising agent was the most powerfull reducing agent which was Zn (s)... I think anyways
Why would answer to pouros material be inert ? its stated in the question its non reactive, so we would just be repeating question. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark SchemeI defintely got -70.5 somewhere(Original post by m1a1tank)
On 3c) where you lot got 794K, i think i got -794K because i think the entropy or enthalpy, can't remember which one, i got it as -70.5.
Did anyone else get this? -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark SchemeI thought it had to be able to conduct electricity otherwise there would be no circuit ? this paper was bullsheet(Original post by kahmed)
I could be wrong but I said that it can't conduct electricity -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Schemei said it acts as a salt bridge so lets ions pass between solutions(Original post by Polioz)
the Zinc EMF value was the most negative not the Cd one.. so the mots weakest oxidising agent was the most powerfull reducing agent which was Zn (s)... I think anyways
Why would answer to pouros material be inert ? its stated in the question its non reactive, so we would just be repeating question. -
Re: CHEM 5 JUNE 12 Section A Unofficial Mark Schemeisnt that the same thing as conducting electricity ?(Original post by Yosemite80)
i said it acts as a salt bridge so lets ions pass between solutions