GCSE Question

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  1. non's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,621
    GCSE Question
    Q1. rearange S=2pidsqrthh^2+d^2 i need to make h the subject.

    so far i've got s^2=(2pid)^2 (h^2+d^2)

    i'm not sure if i'm doing it correctly.

    Q2. solve the equation

    7/x+2 + 1/x-1 = 4

    so far i've got

    7x-7 = 4x^2+4x-8 then 4x2-3x-1=0

    factorised it

    -3+or-(sqrt3^2-4x4x-1)/8

    i got x = 0.25 or -1 which i think is wrong.

    Q3. bag contains 6 red disks, 4 blue disks and 5 green disks.
    A fair dice has 4 red faces and 2 blue faces.

    a disk is taken at random from bag and the colour is recorded.
    then dice is thrown twice and each time colour of face it lands on is recorded.

    work out probability that, of the three colours that are recorded, exactly 2 are the same.
    Last edited by non; 19-06-2012 at 22:51.
  2. Mrbawby's Avatar
    • Junior Member
    • Posts: 32
    Re: GCSE Question
    For question two wouldn't you * the botoms by eachother
  3. non's Avatar
    • Peer Of The TSR Realm
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    Re: GCSE Question
    (Original post by Mrbawby)
    For question two wouldn't you * the botoms by eachother
    i'm not sure sorry.
  4. Mrbawby's Avatar
    • Junior Member
    • Posts: 32
    Re: GCSE Question
    7/x+2+1/x-1=4
    (x-1). (x+2)
    (7x-7)+(x+2)/(x+2)(x-1)=4
    7x-7=4x-4
    7x=4x+3
    3x=3
    X=1
    Btw i havent started unit 2 so it may be wrong
    Last edited by Mrbawby; 20-06-2012 at 00:01.
  5. usycool1's Avatar
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    • Location: Kent
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    Re: GCSE Question
    (Original post by Mrbawby)
    7/x+2+1/x-1=4
    (x-1). (x+2)
    (7x-7)+(x+2)/(x+2)(x-1)=4
    7x-7=4x-4

    7x=4x+3
    3x=3
    X=1
    Btw i havent started unit 2 so it may be wrong
    You have to multiply the 4 by (x-1)(x+2) too.

    And you can't cancel out (x+2) in the lines in bold
    Last edited by usycool1; 20-06-2012 at 20:24.
  6. Mrbawby's Avatar
    • Junior Member
    • Posts: 32
    Re: GCSE Question
    Nope, i *7 by x-1 and 1 by x+2 buy like i said i may be wrong
  7. usycool1's Avatar
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    • Location: Kent
    • Posts: 6,546
    Re: GCSE Question
    (Original post by Mrbawby)
    Nope, i *7 by x-1 and 1 by x+2 buy like i said i may be wrong
    Ah, I see. You have to multiply the 4 by (x-1)(x+2) too
  8. Mrbawby's Avatar
    • Junior Member
    • Posts: 32
    Re: GCSE Question
    Uh you sure 7(x-1)+1(x+2)/x^2+x-2=4 right? Mind doing the question for us
  9. usycool1's Avatar
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    • Location: Kent
    • Posts: 6,546
    Re: GCSE Question
    (Original post by Mrbawby)
    Uh you sure 7(x-1)+1(x+2)/x^2+x-2=4 right? Mind doing the question for us
    I'll post a different example and you guys can try the original question on your own

    Spoiler:
    Show

    \dfrac{1}{x+7}+\dfrac{3}{x+4}=2

    Multiply everything by (x+7)(x+4):

    1(x+4)+3(x+7)=2[(x+7)(x+4)]

    Simplify it:

    x+4+3x+21=2[x^2+4x+7x+28]

    4x+25=2[x^2+11x+28]

    4x+25=2x^2+22x+56

    Rearrange the equation to get 0 on one side:

    0=2x^2+18x+31

    It can't be factorised, so use the quadratic formula to get:

    x=-6.68 OR 2.32
  10. non's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,621
    Re: GCSE Question
    (Original post by usycool1)
    I'll post a different example and you guys can try the original question on your own

    Spoiler:
    Show

    \dfrac{1}{x+7}+\dfrac{3}{x+4}=2

    Multiply everything by (x+7)(x+4):

    1(x+4)+3(x+7)=2[(x+7)(x+4)]

    Simplify it:

    x+4+3x+21=2[x^2+4x+7x+28]

    4x+25=2[x^2+11x+28]

    4x+25=2x^2+22x+56

    Rearrange the equation to get 0 on one side:

    0=2x^2+18x+31

    It can't be factorised, so use the quadratic formula to get:

    x=-6.68 OR 2.32
    thanks i think i've got it. 0.95 and -1.70
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