C4 Gradient Q
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C4 Gradient Qhttp://blogs.thegrangeschool.net/mat...oklet-2012.pdf
Guys can anyone help with Jan 06 q.5(ii)? I got dy/dx as 1/t from the previous q, but when I do y-2p = 1/t (x-p^2) and tidy it up, I don't get what they are looking for...Any ideas?
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Re: C4 Gradient QDid you change that t in the gradient to a p when you put it in the eq of a line?(Original post by Next Level)
http://blogs.thegrangeschool.net/mat...oklet-2012.pdf
Guys can anyone help with Jan 06 q.5(ii)? I got dy/dx as 1/t from the previous q, but when I do y-2p = 1/t (x-p^2) and tidy it up, I don't get what they are looking for...Any ideas?
Cheers
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Re: C4 Gradient QHow does that work?(Original post by BabyMaths)
1/t = 1/p
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Re: C4 Gradient QNo I don't get how that works? Can you explain please?(Original post by TheJ0ker)
Did you change that t in the gradient to a p when you put it in the eq of a line?
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Re: C4 Gradient Qx=t^2(Original post by Next Level)
How does that work?
y=2t
The point is (p^2,2p) so clearly t=p.
