[natalie_gs]

Cn someone please explain how you work out the following probability

X~N(4.11, 0.19)




I can't seem to ge the right answer for this probability.

from the z tables i use values of 0.9803 for 2.06

and 0.8665 for 1.11,

so should the answer not be 0.9803-0.8665 ?

the answer in the book is 0.8468

any help appreciated, thanks

[Slumpy]

(Original post by natalie_gs)
Cn someone please explain how you work out the following probability

X~N(4.11, 0.19)




I can't seem to ge the right answer for this probability.

from the z tables i use values of 0.9803 for 2.06

and 0.8665 for 1.11,

so should the answer not be 0.9803-0.8665 ?

the answer in the book is 0.8468

any help appreciated, thanks

It sounds like the calculation you're doing is this:

Can you see why?

[natalie_gs]

(Original post by Slumpy)


It sounds like the calculation you're doing is this:

Can you see why?

Oh yes, so it should be ;



?

thank you!