C4 formula HELP

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  1. Crystal_Heart's Avatar
    • Junior Member
    C4 formula HELP
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    Found this in the C4 ocr spec, what does it mean and what's it for?

    Any help much appreciated, exam's tomorrow!
  2. supabof93's Avatar
    • New Member
    • Location: Milton Keynes
    • Posts: 17
    Re: C4 formula HELP
    I'm not familiar with that formula (I do Edexcel) but essentially what it looks like is that if you have a function x another function, and one of the functions contains the differential of the other, then it integrates like that
  3. aznkid66's Avatar
    • Exalted and Worshipped Member
    • Posts: 922
    Re: C4 formula HELP
    ...That's a formula? I don't recognize it either..

    Well, if you differentiate both sides, you get the chain rule, no?
    Maybe it's some form of
  4. james.h's Avatar
    • Benevolent Member
    • Posts: 698
    Re: C4 formula HELP
    It looks like just an application of the chain rule:

    \displaystyle \frac{\text{d}}{\text{d}x}(f(g(x  )) = f'(g(x)) g'(x)

    Considering that (for "nice" functions) \int_a^b \frac{\text{d}}{\text{d}x}(f(x))  \ \text{d}x = f(b) - f(a), this then gives the formula you've quoted.


    An example of a question in which it may be of use:

    \displaystyle \text{Evaluate:\ }\int_0^{\pi} \sin(\sin(t)) \cos(t)\ \text{d}t

    Spoiler:
    Show
    Take f(t)=-\cos(t) and g(t)=\sin(t).

    Then use the formula. :yep:


    EDIT: In fairness, though, I can't see why it'd be any easier to use this formula than to do such integrals by substitution.
    Last edited by james.h; 20-06-2012 at 16:41.
  5. Crystal_Heart's Avatar
    • Junior Member
    Re: C4 formula HELP
    Thanks everybody for all your help.

    I think you're right and it's just a weird way of putting the chain rule. Just confused me cuz I'd never seen it before. Thanks for clearing that up.
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