My question is about in what scenario to increase the power of the particular integral you choose. In the book (Edexcel FP2) it says if the particular integral is in the complementary function then you increase the power of or or whatever the variable is.
I thought this was okay until I came across this example:
I need to find the general solution so did the standard "use the auxiliary equation to find the complementary function and then find the particular integral and put the two together to make the general solution".
So complementary function =
I saw that there is the term in both the given differential equation and also in the complementary function so I assumed I had to increase the power of so I tried and differentiated twice to get and and then substituted back into the differential to try and solve for but I just get . Then I increased the power again and used but this time the equations I got contradictory values of .
Then I resorted to looking at the mark scheme and saw that they used and it all worked when I used it.
Why does the rule not work? Or is it because the term in the complementary function is and and not actually ?
p.s. apologies for the slightly waffley question, I got overexcited whilst trying LaTeX
FP2 Second Order Differentials
|Applying to Uni? Let Universities come to you. Click here to get your perfect place||20-10-2014|
OfflineReputationRep:(Original post by Windows7Pro)
- 0 followers
Or is it because the term in the complementary function is and and not actually ?
If the solution was + then you would need to multiply by t as it has one root of -1
If the solution was then you'd multiply by as it has repeated roots of -1
Hope this helps!
Ahhhhh I see I see. Thanks for confirming that.
RegisterThanks for posting! You just need to create an account in order to submit the post Already a member? Sign in
Oops, something wasn't right
please check the following: