STEP II 2012 discussion thread

Maths exam discussion - share revision tips in preparation for GCSE, A Level and other maths exams and discuss how they went afterwards.

Announcements Posted on
Enter our travel-writing competition for the chance to win a Nikon 1 J3 camera 21-05-2013
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Search Thread
Advanced Search
Sign in to Reply
  1. TheMagicMan's Avatar
    261 27-06-2012  17:15
    • Overlord in Training
    • Posts: 2,940
    (Original post by Blutooth)
    Oh, what was the elegant approach to q7?
    I can't remember.... Someone told me it... I'll try to find out


    This was posted from The Student Room's iPhone/iPad App
  2. Cayne96's Avatar
    262 28-06-2012  14:01
    • New Member
    • Posts: 4
    Re: STEP II 2012 discussion thread
    Is there a STEP III discussion thread?
  3. Farhan.Hanif93's Avatar
    263 28-06-2012  14:14
    • Section Moderator
    • PS Helper
    • TSR Idol
    • Location: Cambridge
    Re: STEP II 2012 discussion thread
    (Original post by Cayne96)
    Is there a STEP III discussion thread?
    There will be at half 4. No discussion until then.
  4. cpdavis's Avatar
    264 28-06-2012  16:19
    • Section Moderator
    • PS Helper
    • Pixar Fanatic Moderator
    • Location: London
    Re: STEP II 2012 discussion thread
    (Original post by Farhan.Hanif93)
    There will be at half 4. No discussion until then.
    I've just created a thread for discussion, waiting for it to be approved :yep:
  5. DFranklin's Avatar
    265 28-06-2012  16:32
    • TSR Royalty
    • Location: London
    • Posts: 18,046
    Re: STEP II 2012 discussion thread
    (Original post by cpdavis)
    I've just created a thread for discussion, waiting for it to be approved :yep:
    Done.
  6. Rahul.S's Avatar
    266 28-06-2012  16:34
    • Overlord in Training
    • Location: GREENGATE
    • Posts: 3,496
    Re: STEP II 2012 discussion thread
    half 4 already! totally forgot
  7. B Jack's Avatar
    267 28-06-2012  16:34
    • Full Member
    • Location: Banbury
    • Posts: 90
    Re: STEP II 2012 discussion thread
    Could you post a link to the thread please?
  8. cpdavis's Avatar
    268 28-06-2012  16:35
    • Section Moderator
    • PS Helper
    • Pixar Fanatic Moderator
    • Location: London
    Re: STEP II 2012 discussion thread
  9. joievee's Avatar
    269 05-07-2012  15:48
    • New Member
    • Posts: 10
    Re: STEP II 2012 discussion thread
    hey guys! I know this has been asked loads already, but was just wondering what were your (updated! :P) thoughts on the grade boundaries for this paper! (e.g. a 1 haha) THANKS
  10. Rahul.S's Avatar
    270 05-07-2012  15:54
    • Overlord in Training
    • Location: GREENGATE
    • Posts: 3,496
    Re: STEP II 2012 discussion thread
    (Original post by joievee)
    hey guys! I know this has been asked loads already, but was just wondering what were your (updated! :P) thoughts on the grade boundaries for this paper! (e.g. a 1 haha) THANKS
    I reckon between 65-70 for a 1.
  11. waxwing's Avatar
    271 28-07-2012  17:20
    • Junior Member
    • Location: Shenzhen
    • Posts: 65
    Re: STEP II 2012 discussion thread
    (Original post by jack.hadamard)
    Spoiler:
    Show


    Suppose u_{n - 1} + u_{n - 1} = p u_n, and from u_n(u_n + u_{n + 2}) = u_{n + 1}(u_{n-1} + u_{n + 1}), you get


    \displaystyle \frac{u_n(u_n + u_{n+2})}{u_{n+1}} = p u_n.
    This is further to the discussion on Q8.
    Spoiler:
    Show

    I don't believe that SParm's approach to the proof of the equation with p should be considered satisfactory. The intention, I believe, is to show that the given equation holds for all values of n and only then to substitute alpha,beta and q to find the expression for p.

    Here's what I would write:
    \because u_n(u_{n+2}+u_n)=u_{n+1}(u_{n+1} +u_{n-1}) \therefore \frac{(u_{n+2}+u_n)}{u_{n+1}} = \frac{(u_{n+1}+u_{n-1})}{u_n} \therefore \frac{(u_2+u_0)}{u_1}=\frac{(u_3 +u_1)}{u_2}=\frac{(u_4+u_2)}{u_3 }=\ldots
    and only then to substitute:
    \therefore p = \frac{(u_{n+1}+u_{n-1})}{u_n} = \frac{(u_2+u_0)}{u_1} = \frac{\frac{\beta^2-q^2}{\alpha}+\alpha}{\beta}
    etc.
    Last edited by waxwing; 28-07-2012 at 17:26.
Sign in to Reply
Search Thread
Advanced Search
Share this discussion:  
Useful resources

Articles:

Study Help rules and posting guidelinesStudy Help Member of the Month nominations

Quick Link:

Unanswered Maths Exams Threads

Groups associated with this forum:

View associated groups
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is moderated by:

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22

Registered Office: International House, Queens Road, Brighton, BN1 3XE

Shortcuts

Get Started

TSR Group

Using TSR

Info

Connect with TSR

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.