[fruktas]

(Original post by maksokio)
I think there was a sentence omitted from question one, one that should read "where z=y^n*(something)" like in 2010 STEP II that they forgot to type another sentence about the Useless Eustace question about the range of value of the angles (0<θ<2π).

It may be possible that someone can work out the value of z (as a function of y) by directly integrating the right hand side of the the formula given.

I agree, but the thing is that without this info we couldnt do the question! I ended up saying let z = x^2/4 (without any explanation) in order to show the result given in Q1

[cpdavis]

(Original post by TheMagicMan)
Not in my book. I've consulted about 25 offer holders and about 70% thought it was on the hard side


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I think Farhan told me that it was a nice paper if you liked summing

[desijut]

I guess im alone when i say i did number 1 completely (Yes n=1 and n=-2)... But that's it. I did most of 6 and 7 (15+) and then 3 (not even) partial solutions (2,4,5), possibly about 5 marks each.

By the way this is me being hopeful

I personally thought it was harder than previous years, but im generally not a good judge of what an easy and hard paper is

[TheMagicMan]

(Original post by maksokio)
I think there was a sentence omitted from question one, one that should read "where z=y^n*(something)" like in 2010 STEP II that they forgot to type another sentence about the Useless Eustace question about the range of value of the angles (0<θ<2π).

It may be possible that someone can work out the value of z (as a function of y) by directly integrating the right hand side of the the formula given.

This was my opinion. I thought there was a sentence missing as they usually aren't so blunt at setting up the question


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[fruktas]

(Original post by B Jack)
z=yⁿ(dy/dx)² , but I only worked that out after the exam

That isn't fair, ie a misprint!.. I wasted around 20 minute during the duration of the paper trying to answer it.

[maksokio]

(Original post by B Jack)
I didn't do question 1, but I noticed z=(y^n)(dy/dx)^2

I am afraid that can not be mate, since that wouldnt give (dy/dx)^3 that is contained in the right hand side.

apologies for that, total nonsense

[B Jack]

(Original post by maksokio)
I am afraid that can not be mate, since that wouldnt give (dy/dx)^3 that is contained in the right hand side.

It's factored out, the dy/dx is

[desijut]

(Original post by maksokio)
I am afraid that can not be mate, since that wouldnt give (dy/dx)^3 that is contained in the right hand side.

You forget there was a dy/dx outside the brackets

[TheMagicMan]

(Original post by RacingPro97)
I agree about Q1 - I was worrying this morning thinking that I might be the only person with a printing error or something!

I sent an email to the teacher at my school who's a step problem writer... We'll see what he says... I would be shocked if it actually was a mistake


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[SParm]

Hmmm...I did 8 fully; everything but ii) on 2; everything but the a^3 bit on three; the first two proofs for four; and everything but the inequality on 7. Oh...and I solved first bit of 1 and got z = f(y) (lulwut?)...didn't go well for me. How would you rate my chances of getting a 1 ?_?...(anyone feel free to answer).

[fruktas]

(Original post by desijut)
I guess im alone when i say i did number 1 completely (Yes n=1 and n=-2)... But that's it. I did most of 6 and 7 (15+) and then 3 (not even) partial solutions (2,4,5), possibly about 5 marks each.

By the way this is me being hopeful

I personally thought it was harder than previous years, but im generally not a good judge of what an easy and hard paper is

Yeah, I worked that much out for Q1 that n was -2 or -1/2 cannot remember now, and first part was n =1

[Tobedotty]

I fully did the 3 summation questions (2,4? and 8) and then started 5 and 7. I agree it was quite nice if you like summation, I certainly enjoyed it

[B Jack]

People who did question 4, does 12-16ln2 sound like the answer you got for ii)?

[iluvmaths]

(Original post by TheMagicMan)
I sent an email to the teacher at my school who's a step problem writer... We'll see what he says... I would be shocked if it actually was a mistake


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all u had to say was the n was 1. then sub in the formula for root(y). then solve a simple differential eqn. for the next part, n was 3 or 4. the formula for dz/dx was just a product of two differentials.

[fruktas]

I thought question 2, was sort of a 'typical' STEP question. They guided you through something, and asked you to repeat it all yourself for a different function

[maksokio]

It may be that I am being stupid here for some reason but I think that if z=y^n(dy/dx)^2 then dz/dx=ny^(n-1)(dy/dx)^2+2y^n(dy/dx)(d^2y/dx^2) when the formula reads dz/dx=ny^(n-1)(dy/dx)^3+2y^n(dy/dx)(d^2y/dx^2)

[fruktas]

(Original post by maksokio)
It may be that I am being stupid here for some reason but I think that if z=y^n(dy/dx)^2 then dz/dx=ny^(n-1)(dy/dx)^2+2y^n(dy/dx)(d^2y/dx^2) when the formula reads dz/dx=ny^(n-1)(dy/dx)^3+2y^n(dy/dx)(d^2y/dx^2)

the question did not have a cubed dy/dx it was squared

[Tobedotty]

(Original post by fruktas)
I thought question 2, was sort of a 'typical' STEP question. They guided you through something, and asked you to repeat it all yourself for a different function

I thought that took the piss tbh, I wanted to do something different instead of the same tedious thing again.

[maksokio]

Can someone that somehow did question 1 (with n=1 and n=-2) write it down? I am really interested to see how you worked with z.

[TheMagicMan]

Check what you've got


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