Functions question

Maths and statistics discussion, revision, exam and homework help.

Announcements Posted on
TSR launches Learn Together! - Our new subscription to help improve your learning 16-05-2013
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Sign in to Reply
  1. Zishi's Avatar
    • Peer Of The TSR Realm
    • Location: Sacred Realm
    Functions question


    I have no idea what to do about this question as at x=2, the function is undefined because we're not allowed to divide by zero. Wikipedia says that a continuous function is "In mathematics, a continuous function is a function for which, intuitively, small changes in the input result in small changes in the output". That isn't helping me at all.

    Any help/hints would be appreciated.
    Last edited by Zishi; 30-06-2012 at 04:21.
  2. sputum's Avatar
    • Adored and Respected Member
    • Posts: 425
    Re: Functions question
    (Original post by Zishi)


    I have no idea what to do about this question as at x=2, the function is undefined because we're not allowed to divide by zero. Wikipedia says that a continuous function is "In mathematics, a continuous function is a function for which, intuitively, small changes in the input result in small changes in the output". That isn't helping me at all.

    Any help/hints would be appreciated.
    The idea is that you use the function for the domain (which excludes x=2) and try to 'stitch it together' in some sense by just defining what your function is at x=2 if you can.
    ie can you make this function continuous if you define a value for your function at x=2?

    EDIT: or imagine graphing it. What does it do near x=2?
    Last edited by sputum; 29-06-2012 at 15:58.
  3. Zishi's Avatar
    • Peer Of The TSR Realm
    • Location: Sacred Realm
    Re: Functions question
    (Original post by sputum)
    The idea is that you use the function for the domain (which excludes x=2) and try to 'stitch it together' in some sense by just defining what your function is at x=2 if you can.
    ie can you make this function continuous if you define a value for your function at x=2?

    EDIT: or imagine graphing it. What does it do near x=2?
    As I put values of x to be -1, 0, and 1, I see that values of f(x) increase in negativity, i.e -1.66...,-2.5,-5. So does that mean that value of f(x) as x=2 should be more negative than -5?
  4. dantheman1261's Avatar
    • Full Member
    • Posts: 105
    Re: Functions question
    Do you know what the graph of  f(x) = \frac{1}{x} looks like?

    If so, then then try to sketch  f(x) = \frac{1}{x - 2} and then  f(x) = \frac{5}{x - 2} , by using standard graph sketching rules.

    If not, then what happens when x gets really close to 2 from above? Take x = 2.1, 2.05, 2.01 and see what happens to  \frac{5}{x - 2} . Then try taking x = 1.9, 1.95, 1.99, and see also what happens.

    A continuous function has a precise mathematical definition, but intuitively, it means that you can draw it without taking your pen off the page. Note that  f(x) = x is continuous, as you can easily draw a straight line without ever taking your pen from the page. Do you see what happens to the graph in this case?
    Last edited by dantheman1261; 29-06-2012 at 18:13. Reason: Fractions
  5. Lord of the Flies's Avatar
    • The foul fiend Flibbertigibbet
    • Location: Paris, France
    • Warning points: 2
    Re: Functions question
    (Original post by Zishi)


    I have no idea what to do about this question as at x=2, the function is undefined because we're not allowed to divide by zero. Wikipedia says that a continuous function is "In mathematics, a continuous function is a function for which, intuitively, small changes in the input result in small changes in the output". That isn't helping me at all.

    Any help/hints would be appreciated.
    A function can appear undefined at certain values for which it actually can be defined. The standard way of checking this is by evaluating the limit of the function when the variable approaches the indeterminate value.

    Classic example:

    Spoiler:
    Show

    f(x)=\dfrac{\sin x}{x}

    What happens at 0? We can apply l'Hôpital's rule here, which gives: \displaystyle\lim_{x\to0}\dfrac{  \sin x}{x}=\lim_{x\to0}\cos x=1\Rightarrow f(0)=1

    So f is actually defined for all x even though it appeared to be undefined for 0...


    In your case, evaluate \displaystyle \lim_{x\to 2^{\pm}} \dfrac{5}{x-2} (think of the curve) and see whether the value(s) you get are definite or not. If so, compare your result to the possible answers. A function is continuous if (basically) you can sketch it without taking your pen off the page... Beware though, a function that is defined over a certain domain does not imply it is continuous over that domain, but I don't think you have to worry about that here.
    Last edited by Lord of the Flies; 29-06-2012 at 18:28.
  6. Zishi's Avatar
    • Peer Of The TSR Realm
    • Location: Sacred Realm
    Re: Functions question
    Oh, thanks a lot everyone. I actually didn't think that it's a limits question!
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.