Core Maths 4: Integration/Trig/double and triple angle formulae
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Core Maths 4: Integration/Trig/double and triple angle formulaeHi there
Please could someone take a look at this and advise if I am on the right lines, and maybe give me a little nudge in the right direction to solve the question

Many thanks
Jackie -
Re: Core Maths 4: Integration/Trig/double and triple angle formulaeYou are correct till(Original post by jackie11)
Hi there
Please could someone take a look at this and advise if I am on the right lines, and maybe give me a little nudge in the right direction to solve the question

Many thanks
Jackie
Then how did you wrote,
What you have is

Hint for integrating
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Re: Core Maths 4: Integration/Trig/double and triple angle formulaeIt seems you have taken the complicated route.(Original post by jackie11)
Hi there
Please could someone take a look at this and advise if I am on the right lines, and maybe give me a little nudge in the right direction to solve the question
Many thanks
Jackie
Try considering
by parts 
EDIT: actually don't -
to myself
Last edited by Lord of the Flies; 03-07-2012 at 10:16. -
Re: Core Maths 4: Integration/Trig/double and triple angle formulaeI think your route is also complicated.(Original post by Lord of the Flies)
It seems you have taken the complicated route.
Try considering
by parts
The method that Lukas gave is the best way to tackle this question. -
Re: Core Maths 4: Integration/Trig/double and triple angle formulaeI don't mean the OP's method. I mean the method given by lukas1051:(Original post by Lord of the Flies)
What method?
Also, I don't see how an integration by parts is more complicated than the stream of equations in the OP:
Without difficulty, by parts twice gives:
![\displaystyle\int\cos x\cos^2 x=[\sin x \cos^2]-2\int\sin^2 x\cos x+[\sin^3x]+2\int\sin^2x\cos x \displaystyle\int\cos x\cos^2 x=[\sin x \cos^2]-2\int\sin^2 x\cos x+[\sin^3x]+2\int\sin^2x\cos x](http://www.thestudentroom.co.uk/latexrender/pictures/7c/7c2f5cb8fcb2cb66c4643f46547e780a.png)

Both of these integrals are easy. It is far quicker and "nicer" to do this rather than use integration by parts twice.Last edited by notnek; 03-07-2012 at 10:09. -
Re: Core Maths 4: Integration/Trig/double and triple angle formulaeYes, just realised this...(Original post by notnek)

It is far quicker and "nicer" to do this rather than use integration by parts.
Besides I made an idiotic mistake in my post so I'm going to leave now...
Last edited by Lord of the Flies; 03-07-2012 at 10:12. -
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Re: Core Maths 4: Integration/Trig/double and triple angle formulaeyes you are right, omg what a silly mistake to make haha(Original post by raheem94)
You are correct till
Then how did you wrote,
What you have is
[/spoiler]
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Re: Core Maths 4: Integration/Trig/double and triple angle formulae(Original post by jackie11)
ok I am still not getting the right answer for this, am I on the right lines?
should remind you of something...
Hint:
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Re: Core Maths 4: Integration/Trig/double and triple angle formulaeYou main mistake is in saying that(Original post by jackie11)
ok I am still not getting the right answer for this, am I on the right lines?

You can't split up a product in an integral like this. In general,

Instead, you need to integrate
as one expression.
Try differentiating
and see what you get. This should give you a big clue as to what the integral of
is.
Last edited by notnek; 03-07-2012 at 14:43. -
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Re: Core Maths 4: Integration/Trig/double and triple angle formulaeUsing the chain rule, differentiating sin³ x gives me;
-3 sin² x cos x
So the integral of cos x sin² x is -1/3 sin³ x.
Am I on the right lines now? lol -
Re: Core Maths 4: Integration/Trig/double and triple angle formulaeAlmost - you made a sign mistake. The derivative of sin is cos, not -cos.(Original post by jackie11)
Using the chain rule, differentiating sin³ x gives me;
-3 sin² x cos x
So the integral of cos x sin² x is -1/3 sin³ x.
Am I on the right lines now? lol -
Re: Core Maths 4: Integration/Trig/double and triple angle formulaeAlmost, but the derivative of(Original post by jackie11)
Using the chain rule, differentiating sin³ x gives me;
-3 sin² x cos x
So the integral of cos x sin² x is -1/3 sin³ x.
Am I on the right lines now? lol
shouldn't have a negative sign since the derivative of
is
not
.
