Factoring!

Maths and statistics discussion, revision, exam and homework help.

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  1. kenny629's Avatar
    • Junior Member
    • Posts: 72
    Factoring!
    Hey guys, just need to clarify the correct procedure for this factorisation.

    4(3x^2-4) factors to; 12(x^2-4/3) factors to; 12((x+(2/sqrt3))*((x-(2/sqrt3))

    Hope someone can help as this has me stumped!!!

    Thanks a heap!
  2. dantheman1261's Avatar
    • Full Member
    • Posts: 105
    Re: Factoring!
    Looks good to me!
  3. kenny629's Avatar
    • Junior Member
    • Posts: 72
    Re: Factoring!
    Sorry i didnt explain myself properly!!
    This example was in the book, im unsure of how they achieved it...
  4. the bear's Avatar
    • TSR Demigod
    • Location: Linton Travel Tavern
    • Posts: 7,204
    Re: Factoring!
    it is using the idea of difference of two squares to split the original bracket into two smaller ones.
  5. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Factoring!
    (Original post by kenny629)
    Hey guys, just need to clarify the correct procedure for this factorisation.

    4(3x^2-4) factors to; 12(x^2-4/3) factors to; 12((x+(2/sqrt3))*((x-(2/sqrt3))

    Hope someone can help as this has me stumped!!!

    Thanks a heap!
    Spoiler:
    Show

     \displaystyle 4 ( 3x^2 - 4)  = 12x^2 - 16 = 12 \left( x^2 - \frac{16}{12} \right) = 12 \left( x^2 - \frac{4}{3} \right)  \\ = 12 \left( x^2 - \left( \frac2{\sqrt3} \right)^2  \right)  = 12 \left( x - \frac2{\sqrt3} \right)  \left( x + \frac2{\sqrt3} \right)
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