Algebraic Fractions

Maths and statistics discussion, revision, exam and homework help.

This thread is sponsored by:
Announcements Posted on
Important: please read these guidelines before posting about exams on The Student Room 28-04-2013
Sign in to Reply
  1. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Algebraic Fractions
    I have this question

    But I'm getting the wrong answer.

    Click image for larger version. 

Name:	Fraction.gif 
Views:	37 
Size:	1.1 KB 
ID:	162793
  2. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    I have to work out the value of X but I don't know how to.
  3. notnek's Avatar
    • TSR Demigod
    • Location: Bangkok, Thailand
    Re: Algebraic Fractions
    You are correct so far. Next, you can silmplify the 3x and the 4x on the numerator.

    After that, move the x^2+x to the right-hand side i.e. multiply both sides by x^2+x. Then simplify and solve.
  4. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    (Original post by notnek)
    You are correct so far. Next, you can silmplify the 3x and the 4x on the numerator.

    After that, move the x^2+x to the right-hand side i.e. multiply both sides by x^2+x. Then simplify and solve.
    So I've simplified the numerator,

    Click image for larger version. 

Name:	Fraction.gif 
Views:	25 
Size:	870 Bytes 
ID:	162845
    and what exactly do you mean when you times the whole fraction by x^2
  5. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    And what's the best method to solve these type of questions.

    The book shows a different method to what I am doing,

    However I am now starting to get confused when it comes to simplifying algebraic fraction when it involves cancelling things out etc.
  6. DarkPeople's Avatar
    • Respected Member
    • Posts: 182
    Re: Algebraic Fractions
    Multiply the whole equation by (x^2 + x) and then rearrange to get it in the form of ax^2 + bx + c = 0 then factorise to work out the values of x
  7. TheGoat's Avatar
    • Exalted Member
    • Posts: 291
    Re: Algebraic Fractions
    (Original post by zed963)
    And what's the best method to solve these type of questions.

    The book shows a different method to what I am doing,

    However I am now starting to get confused when it comes to simplifying algebraic fraction when it involves cancelling things out etc.
    Usually you just have to get rid of all denominators and then solve for x.
  8. TenOfThem's Avatar
    • No --- I am a Newbie --- Honest
    Re: Algebraic Fractions
    (Original post by zed963)
    So I've simplified the numerator,

    Click image for larger version. 

Name:	Fraction.gif 
Views:	25 
Size:	870 Bytes 
ID:	162845
    and what exactly do you mean when you times the whole fraction by x^2
    You seem to have mislaid the whole =1 part of the question
  9. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    (Original post by TenOfThem)
    You seem to have mislaid the whole =1 part of the question
    Oops, so what is the best way of doing this question?

    And please can you show me an example solution to this type of question.

    Thanks.
  10. notnek's Avatar
    • TSR Demigod
    • Location: Bangkok, Thailand
    Re: Algebraic Fractions
    (Original post by zed963)
    Oops, so what is the best way of doing this question?

    And please can you show me an example solution to this type of question.

    Thanks.
    e.g.

    \displaystyle \frac{2x+1}{x^2-1} = 1 \implies 2x+1 = x^2-1

    Here I've moved the x^2-1 to the right-hand-side. Does this make sense to you?

    Try to do a similar thing for your question. Then simplify and solve the resulting quadratic equation.
  11. TenOfThem's Avatar
    • No --- I am a Newbie --- Honest
    Re: Algebraic Fractions
    Your method is fine

    you are at the point of

    \frac{3-x}{x^2+x} = 1

    So that means

    3-x = x^2+x

    Just a quadratic
  12. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    (Original post by TenOfThem)
    Your method is fine

    you are at the point of

    \frac{3-x}{x^2+x} = 1

    So that means

    3-x = x^2+x

    Just a quadratic
    so

    x^2+2x-3

    when rearranged.
  13. notnek's Avatar
    • TSR Demigod
    • Location: Bangkok, Thailand
    Re: Algebraic Fractions
    (Original post by zed963)
    so

    x^2+2x-3

    when rearranged.
    What happened to the equals sign?

    If you start with an equation then you should still have an equation after you rearrange.
  14. TenOfThem's Avatar
    • No --- I am a Newbie --- Honest
    Re: Algebraic Fractions
    (Original post by notnek)
    What happened to the equals sign?
    Again
  15. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    (Original post by notnek)
    What happened to the equals sign?

    If you start with an equation then you should still have an equation after you rearrange.
    I forgot the =0 bit

    Typo

    But from then on when I factorise the equation I get

    (x-1)(x+3)=0

x=1,-3

    Thank you for explaining how to solve this equation to me.

    Much appreciated
  16. TenOfThem's Avatar
    • No --- I am a Newbie --- Honest
    Re: Algebraic Fractions
    (Original post by zed963)

    Much appreciated
    Sometimes you get a fraction on the RHS too, then it makes sense to simply multiply through by the common denominator from the start

    eg

    \frac{3}{x} + \frac{1}{2x} = \frac{1}{x+1}

    would become

    \frac{(3)(x)(2x)(x+1)}{x} + \frac{(1)(x)(2x)(x+1)}{2x} = \frac{(1)(x)(2x)(x+1)}{x+1}

    which gives

    (3)(2x)(x+1) + (1)(x)(x+1) = (1)(x)(2x)

    giving

    6x^2 + 6x + x^2 + x = 2x^2

    5x^2 + 7x = 0
  17. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    I have this question and so far I have an idea of what I am doing but from there on I don't know what to do

    Here's my working out.

    Click image for larger version. 

Name:	Fraction 2.gif 
Views:	32 
Size:	2.2 KB 
ID:	162860

    How should I carry on with this question?
  18. Groat's Avatar
    • PS Helper
    • ±
    Re: Algebraic Fractions
    (Original post by zed963)
    I have this question and so far I have an idea of what I am doing but from there on I don't know what to do

    Here's my working out.

    Click image for larger version. 

Name:	Fraction 2.gif 
Views:	32 
Size:	2.2 KB 
ID:	162860

    How should I carry on with this question?
     2x^2 = 5

    Can you work it out from there?
  19. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    (Original post by Groat)
     2x^2 = 5

    Can you work it out from there?
    Yes I originally thought of that

    so if I did the root of 2.5 it gives +1.58 and -1.58
  20. zed963's Avatar
    • Overlord in Training
    • Posts: 2,161
    Re: Algebraic Fractions
    The answer in the book is -1.5 and 2
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.