How to do this?

Maths and statistics discussion, revision, exam and homework help.

Announcements Posted on
TSR launches Learn Together! - Our new subscription to help improve your learning 16-05-2013
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Sign in to Reply
  1. sabre2th1's Avatar
    • Exalted and Worshipped Member
    • Location: Southampton
    • Posts: 1,046
    How to do this?


    I know you have to equate the real and imaginary parts of the equation...

    But with 'abi' how do you know whether it is (a x bi) or (b x ai) or (abi)..

    In other words, what do I equate 3a-b to and what do I equate 12 to
  2. Augmented hippo's Avatar
    • Full Member
    • Posts: 121
    Re: How to do this?
    (Original post by sabre2th1)


    I know you have to equate the real and imaginary parts of the equation...

    But with 'abi' how do you know whether it is (a x bi) or (b x ai) or (abi)..

    In other words, what do I equate 3a-b to and what do I equate 12 to
    a*bi is the same as b*ai and abi. The key is equating the real and imaginary parts of both sides of the equation.
  3. Lord of the Flies's Avatar
    • The foul fiend Flibbertigibbet
    • Location: Paris, France
    Re: How to do this?
    (Original post by sabre2th1)


    I know you have to equate the real and imaginary parts of the equation...

    But with 'abi' how do you know whether it is (a x bi) or (b x ai) or (abi)..

    In other words, what do I equate 3a-b to and what do I equate 12 to
    LHS real part is 0, imaginary part is ab. So you equate 3a-b to 0 and 12 to ab.
  4. sabre2th1's Avatar
    • Exalted and Worshipped Member
    • Location: Southampton
    • Posts: 1,046
    Re: How to do this?
    (Original post by Augmented hippo)
    a*bi is the same as b*ai and abi. The key is equating the real and imaginary parts of both sides of the equation.
    (Original post by Lord of the Flies)
    LHS real part is 0, imaginary part is ab. So you equate 3a-b to 0 and 12 to ab.
    so if we had a + bi, a is the real part but bi is imaginary? Could one say 'b' on its own is real?

    Thanks
  5. Lord of the Flies's Avatar
    • The foul fiend Flibbertigibbet
    • Location: Paris, France
    Re: How to do this?
    (Original post by sabre2th1)
    so if we had a + bi, a is the real part but bi is imaginary? Could one say 'b' on its own is real?

    Thanks
    This is how it works:

    z=a+bi,\;\;(a,b)\in\mathbb{R}

    \operatorname{Re} (z)=a

    \operatorname{Im} (z)=b

    \operatorname{Im} (z)\neq bi

    (a part is always a real number, picture them as coefficients (real part is the "coefficient of the unit of real numbers, 1", imaginary part is the "coefficient of the unit of complex numbers, i"))
    Last edited by Lord of the Flies; 16-07-2012 at 17:43.
  6. f1mad's Avatar
    • TSR Demigod
    • Posts: 5,423
    Re: How to do this?
    Equate real and imaginary parts.

    Hint: The real part of the LHS is zero.
  7. sabre2th1's Avatar
    • Exalted and Worshipped Member
    • Location: Southampton
    • Posts: 1,046
    Re: How to do this?
    (Original post by Lord of the Flies)
    This is how it works:

    z=a+bi,\;\;(a,b)\in\mathbb{R}

    \operatorname{Re} (z)=a

    \operatorname{Im} (z)=b

    \operatorname{Im} (z)\neq bi

    (a part is always a real number, picture them as coefficients (real part is the "coefficient of the unit of real numbers, 1", imaginary part is the "coefficient of the unit of complex numbers, i"))
    regarding the bold part, what do you mean with a part? btw I understand that the imaginary part is the coefficient of i..

    Thanks


    (Original post by f1mad)
    Equate real and imaginary parts.

    Hint: The real part of the LHS is zero.
    i understand now, thanks..
  8. Lord of the Flies's Avatar
    • The foul fiend Flibbertigibbet
    • Location: Paris, France
    Re: How to do this?
    (Original post by sabre2th1)
    regarding the bold part, what do you mean with a part? btw I understand that the imaginary part is the coefficient of i..

    Thanks
    A complex number z has a real part a and an imaginary part b such that z=a+bi

    It's basic terminology!
  9. sabre2th1's Avatar
    • Exalted and Worshipped Member
    • Location: Southampton
    • Posts: 1,046
    Re: How to do this?
    (Original post by Lord of the Flies)
    A complex number z has a real part a and an imaginary part b such that z=a+bi

    It's basic terminology!
    Thank you
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.