binomial distribution: Xi~B(n, p) Yj~B(m, p) Xi+Yj~B(n+m, p)
Maths and statistics discussion, revision, exam and homework help.
-
- Reputation:
- Thread Starter
- Junior Member
- Posts: 47
binomial distribution: Xi~B(n, p) Yj~B(m, p) Xi+Yj~B(n+m, p)Where can I find out (the prove of)this topic?
Any books/ internet materials mention about this topic?
Xi has binomial distribution B(n, p)
Yj has binomial distribution B(m, p)
Xi+Yj has binomial distribution B(n+m, p)
Combine poison distribution
P(
) and P(
)
= P(
)
Last edited by BookInquiry; 17-07-2012 at 06:13. -
- Reputation:
- Adored and Respected Member
- Posts: 595
Re: binomial distribution: Xi~B(n, p) Yj~B(m, p) Xi+Yj~B(n+m, p)Write the Binomials as a sum of Bernoulli's and its obvious
Poisson one can be proved from the MGF, see http://www.proofwiki.org/wiki/Sum_of...les_is_Poisson. You could use the same method to prove the Binomial one. You could also use the univariate transformation theorem for both.Last edited by poohat; 17-07-2012 at 06:36.
