[zed963]

What am I doing wrong on this question.

[Plato's Trousers]

(Original post by zed963)
What am I doing wrong on this question.

just draw the line and find the solutions like you did with the other graph (first part of the question)

hint - the easy way to draw is to draw and translate the graph "down" the y-axis by 19 units

[TenOfThem]

you needed the graph of y=5-2x

[TenOfThem]

(Original post by Plato's Trousers)
just draw the line and find the solutions like you did with the other graph

hint - the easy way to draw is to draw and translate the graph "down" the y-axis by 19 units

That is not the method required by the question

[Plato's Trousers]

(Original post by TenOfThem)
That is not the method required by the question

tbh it's not that clear what method the question is asking for. And god knows what that stuff at the bottom is supposed to mean. y=-6 [2] x=-1 etc

[Plato's Trousers]

another way would be to draw and see where they intersect

(work out what gives you)

[TenOfThem]

(Original post by Plato's Trousers)
tbh it's not that clear what method the question is asking for

It says --- by drawing a suitable line

(Original post by Plato's Trousers)
And god knows what that stuff at the bottom is supposed to mean. y=-6 [2] x=-1 etc

They are zed's incorrect answers [and the marks available]

[steve2005]

(Original post by zed963)
What am I doing wrong on this question.

The web site this question comes from is littered with errors.

[Plato's Trousers]

(Original post by steve2005)
The web site this question comes from is littered with errors.

yeah. It's a pretty poor question, tbh. Rather ambiguous

[steve2005]

(Original post by Plato's Trousers)
yeah. It's a pretty poor question, tbh. Rather ambiguous

It's not ambiguous . The suggested solutions are simply rubbish.

[Plato's Trousers]

(Original post by steve2005)
It's not ambiguous . The suggested solutions are simply rubbish.

and what is that random blue line doing on the graph?

[TenOfThem]

(Original post by Plato's Trousers)
and what is that random blue line doing on the graph?

That will also be Zed's answer

[TenOfThem]

(Original post by steve2005)
The suggested solutions are simply rubbish.

What suggested solutions?

Where are you seeing errors from the site on the attachment given

[steve2005]

(Original post by TenOfThem)
What suggested solutions?

Where are you seeing errors from the site on the attachment given

Sorry, I thought the 'answers' at the bottom were answers that the user had to select.

[TenOfThem]

(Original post by steve2005)
Sorry, I thought the 'answers' at the bottom were answers that the user had to select.

this is what the page looks like



though i agree that the site is far from perfect

[TheGoat]

..Just write the coordinates of the point where the line crosses the X and Y axis?

[Plato's Trousers]

(Original post by TenOfThem)
That will also be Zed's answer

but he appears to have entered y= -6 as his answer. That blue line is not y= -6

[TenOfThem]

(Original post by Plato's Trousers)
but he appears to have entered y= -6 as his answer. That blue line is not y= -6

No

But we had already established that he did not know what he was doing

Hence the thread

[TenOfThem]

(Original post by TheGoat)
..Just write the coordinates of the point where the line crosses the X and Y axis?

This is not correct

[Plato's Trousers]

(Original post by TenOfThem)
No

But we had already established that he did not know what he was doing

Hence the thread

I thought you were saying he had to enter the line required in the y= box. Then the program would draw it on the graph? He hasn't entered the equation of that line so how did it appear on the graph?