The Student Room Group
Reply 1
cat123
What 2 isomeric alkenes are formed when 2-bromo-3methylbutane reacts with ethanolic potassium hydroxide? I cant seem to work this out as i keep drawing out the mechanism but not getting any 2 isomeric alkenes! do these have to be geometric?

thanks:smile:


ethanolic KOH, results in formation of alkene - its an elimination

and since the bromo must be eliminated, the double bond could end up either side of the 2-carbon. so you'd get:
3-methylbut-1-ene
3-methylbut-2-ene

i think so anyway
Reply 2
but do all these type of elimination reactions produce geometric isomers?

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