Semi-Circle
Maths and statistics discussion, revision, exam and homework help.
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Re: Semi-CircleYes, that will give you the circumference of the whole circle.(Original post by zed963)
Am I meant to be using c=pi*d
But here you have half a circle. So how can you use C to find the perimeter? -
Re: Semi-CircleDivide it by 2(Original post by notnek)
Yes, that will give you the circumference of the whole circle.
But here you have half a circle. So how can you use C to find the perimeter? -
Re: Semi-CircleYes and then add on the diameter to find the perimeter.(Original post by zed963)
Divide it by 2 -
Re: Semi-Circle40m Well not exactly 40 its a bit over.(Original post by notnek)
If you wrap the cotton around the reel one time then the length will be equal to the circumference of the reel.
So if you wrap it around 500 times then the length is...
What I did was * the radius by 2 and then by pi
Then times the circumference by 500 and then divide it by 100 to get the answer in metres. -
Re: Semi-CircleYes that's right.(Original post by zed963)
40m Well not exactly 40 its a bit over.
What I did was * the radius by 2 and then by pi
Then times the circumference by 500 and then divide it by 100 to get the answer in metres.
I'm not sure if you needed my help for that one
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Re: Semi-CircleYour method is correct.(Original post by zed963)
What am I doing wrong?
I worked out the area of the circle and then the rectangle and then I subtracted the rectangle from the circle but I'm not getting the right answer.
Post your working with your answer and the correct answer. -
Re: Semi-CircleWell to find the area of the circle I used the formula a=pir^2(Original post by notnek)
Your method is correct.
Post your working with your answer and the correct answer.
I know that the diameter of the circle is 10 therefore the radius will be half the diameter which is 5
substituting the value into the formula I get 78.54
I then work out the area of the rectangle which is 48
78.54-48=30.54cm^2
but the answer in the book is 20.5cm^2 -
Re: Semi-Circle
I got...
((25 * pi) / 2) + 25 = 64.26990816987241548078304229099 4
25 * pi gives you the perimeter of a circle which a diameter of length 25. Halving that number gives you the length of the curved edge of the semi-circle. Adding 25 adds the length of the bottom-line of the semi-circle, giving the length of semi-circle's total perimeter.
If I've made a mistake here I'd appreciate a correction, but this reasoning seems to make sense to me. -
Re: Semi-CircleYour answer is correct.(Original post by zed963)
Well to find the area of the circle I used the formula a=pir^2
I know that the diameter of the circle is 10 therefore the radius will be half the diameter which is 5
substituting the value into the formula I get 78.54
I then work out the area of the rectangle which is 48
78.54-48=30.54cm^2
but the answer in the book is 20.5cm^2