The Student Room Group
Reply 1
silly_billy
show that the substitution u = sin x transforms the integral

6/(cosx(2-sinx)) .dx

u = sinx
du/dx = cosx
dx = du/cosx

6/cosx(2-u) du/cosx
= 6/cos2x(2-u) du
= 6/(1-sin2x)(2-u) du
= 6/(1-u2)(2-u) du
Slightly messy but should be easier to understand.
Reply 2
thank you!

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