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trigonometric identity help

If you have the trigonometric identity tanx+cotx = secxcosecx

this can be verified by rewriting tanx and cotx in their sinx and cosx forms, getting a common denominator etc.

However, if you were to go down the root of tanx + 1/tanx

tan^2x/tanx + 1/tanx

(tan^2x+1)/tanx

sec^2x/tanx

however, can this be simplified to give secxcosecx or have I made an error I haven't seen?
Hey there,

So, sec^2x/tanx = (1/cos^2x) / (sinx/cosx) = 1/cos^2x * cosx/sinx = 1/cosxsinx = secxcosecx.

I think LOL. It's been a while since I've done trig, but it looks OK to me!

Hope this helped. :tongue:
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Thank you!

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