Heres the question: Integrate (sec x)^2 (3tanx – 4)
I got this far
(1 + (tan x)^2)(3tanx - 4)
{using the trig identity (sec x)^2 = 1 + (tan x)^2}
Mulitplied it out:
3tanx - 4 + 3(tanx)^3 - 4(tanx)^2 dx
Is this correct so far, and to integrate would i just let x=tanx and go from there?
Thanks in advance.