Complex numbers
Maths and statistics discussion, revision, exam and homework help.
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Re: Complex numbersNot the kind of response I was looking for...(Original post by Slumpy)
What's an expression for z+i? And how do you move from a complex number to it's conjugate? -
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Re: Complex numbersWell, it's normally the kind of response you get. On here (particularly in Maths threads) we can either give you the answer or guide you there. Most people here prefer the latter, as at least you're coming the conclusion yourself and learning (also it avoids giving answers to homework cheaters).(Original post by Jooooshy)
Not the kind of response I was looking for... -
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Re: Complex numbersSorry, I thought you were being genuine. I have self-taught FP1, so I lack a lucid understanding...:-((Original post by The Polymath)
Well, it's normally the kind of response you get. On here (particularly in Maths threads) we can either give you the answer or guide you there. Most people here prefer the latter, as at least you're coming the conclusion yourself and learning (also it avoids giving answers to homework cheaters).
Would (z+i) be x + i(y+1)? Then (z+i)* be x - i(y+1)? -
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Re: Complex numbersWell then you're on the wrong forum. The study help forum is for helping students learn, not giving them answers.(Original post by Jooooshy)
Not the kind of response I was looking for... -
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Re: Complex numbersIt's been three months and I've already forgotten everything(Original post by Jooooshy)
Sorry, I thought you were being genuine. I have self-taught FP1, so I lack a lucid understanding...:-(
Would (z+i) be x + i(y+1)? Then (z+i)* be x - i(y+1)?
Sorry, I can't help you - I really need to quickly skim over the book again, this is just embarrassing... -
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Re: Complex numbersYep that's right. Isn't it better when you manage it yourself?(Original post by Jooooshy)
Sorry, I thought you were being genuine. I have self-taught FP1, so I lack a lucid understanding...:-(
Would (z+i) be x + i(y+1)? Then (z+i)* be x - i(y+1)?
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Re: Complex numbersYes.(Original post by Jooooshy)
Sorry, I thought you were being genuine. I have self-taught FP1, so I lack a lucid understanding...:-(
Would (z+i) be x + i(y+1)? Then (z+i)* be x - i(y+1)? -
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Re: Complex numbersYou obviously didn't read my post correctly. I didn't ask what the answer was, I asked how to do it.(Original post by Intriguing Alias)
Well then you're on the wrong forum. The study help forum is for helping students learn, not giving them answers.
As for my reply, I thought he was seeking further guidance from me! I thought the user genuinely didn't know, reinforced by the profile description of 'No GCSEs. No A-levels.' which I later realised to be satirical. Give me a break. -
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Re: Complex numbersOh no, it's totally true. I went to school in Scotland(Original post by Jooooshy)
You obviously didn't read my post correctly. I didn't ask what the answer was, I asked how to do it.
As for my reply, I thought he was seeking further guidance from me! I thought the user genuinely didn't know, reinforced by the profile description of 'No GCSEs. No A-levels.' which I later realised to be satirical. Give me a break.
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Re: Complex numbersAh, I see!
Whilst you're online, would you care to check over another answer for me?
The second part of the question is solve (z+i)* = 2iz + 1 giving your answer in the form a + bi
Do I write z =... as my answer, or just the a + bi?
I fiddled it down to simultaneous equations and got a = -1 and b = 1... Is this correct?Last edited by Jooooshy; 12-09-2012 at 21:58. -
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Re: Complex numbersLooks fine to me. I always tended to write down both, ie(Original post by Jooooshy)
Ah, I see!
Whilst you're online, would you care to check over another answer for me?
The second part of the question is solve (z+i)* = 2iz + 1 giving your answer in the form a + bi
Do I write z =... as my answer, or just the a + bi?
I fiddled it down to simultaneous equations and got a = -1 and b = 1... Is this correct?
a=-1, b=1, so z=-1+i (doesn't take any time, and covers all bases)
