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C3 Algebraic Fractions

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    EXPRESS

    (x-10)/((x-3)(x+4))-(x-8)/((2x-1)(x-3))


    AS A SINGLE FRACTION IN ITS SIMPLEST FORM.

    THANK YOU
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    HELP !!!!!
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    So what is the common denominator?
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    (X-3)
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    (Original post by Vinkal)
    EXPRESS

    (x-10)/((x-3)(x+4))-(x-8)/((2x-1)(x-3))


    AS A SINGLE FRACTION IN ITS SIMPLEST FORM.

    THANK YOU
    In order to express this as a single fraction, you need both of the above terms to have a common denominator. You should be able to see that denominators of both terms already have a common factor of x-3. Try multiplying the first fraction by \dfrac{2x-1}{2x-1} and the second by \dfrac{x+4}{x+4}, thinking about why this is valid and why it helps.
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    5

    thank you

    so i got (x-14)/((x+4)(2x-1)) can that be simplified or is it in its simplest form
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    (Original post by Vinkal)
    thank you

    so i got (x-14)/((x+4)(2x-1)) can that be simplified or is it in its simplest form
    Cannot be simplified
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    (Original post by Vinkal)
    thank you

    so i got (x-14)/((x+4)(2x-1)) can that be simplified or is it in its simplest form
    Since the numerator is linear whilst the denominator is a quadratic (importantly expressed in it's simplest form), this can only be simplified further if the numerator is some multiple of one of the two linear factors in the denominator. Is this the case?
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    (x-10)/((x-3)(x+4))-(x-8)/((2x-1)(x-3))

    (X-10)(2X-1) (X-8)(X-3 )
    (X-3)(X+4)(2X-1) - (X-3)(X+4)(2X-1)

    (2X2-21X+10) (X2 -4X-32 )
    (X-3)(X+4)(2X-1) - (X-3)(X+4)(2X-1)


    (X2-17X+42)
    (X-3)(X+4)(2X-1)

    (X-3)(X-14)
    (X-3)(X+4)(2X-1)

    (X-14)
    (X+4)(2X-1)
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    (Original post by Vinkal)
    (x-10)/((x-3)(x+4))-(x-8)/((2x-1)(x-3))

    (X-10)(2X-1) (X-8)(X-3 )
    (X-3)(X+4)(2X-1) - (X-3)(X+4)(2X-1)

    (2X2-21X+10) (X2 -4X-32 )
    (X-3)(X+4)(2X-1) - (X-3)(X+4)(2X-1)


    (X2-17X+42) (X-3)(X+4)(2X-1)

    (X-3)(X-14) (X-3)(X+4)(2X-1)

    (X-14) (X+4)(2X-1)
    Hope that was not in response to my deleted post where I had made an error

    To help in the future ... this gives fractions

    \dfrac{x-14}{(x+4)(2x-1)}
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    How do you write fractions in your reply
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    (Original post by Vinkal)
    How do you write fractions in your reply
    If you quote my post with the fraction you will see
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    Thank you for your help duo
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    (Original post by TenOfThem)
    If you quote my post with the fraction you will see

    HOW
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    (Original post by Vinkal)
    HOW
    Click QUOTE for this post and you will see


    \frac{a}{b}
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    or look here

    http://www.thestudentroom.co.uk/wiki/LaTex
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    thank you once again

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