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How to find closed form

I don't understand how to find the closed form equation (Question 2-5)
Can someone help me?
thanks a lot!!!

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Is it an=3an12an2  (a1=a2=2)a_{n} = 3a_{n-1}-2a_{n-2} ~~ (a_{1} = a_{2} = 2)?

Consider the characteristic equation of the recurrence: 2x23x+1=0.2x^2-3x+1 = 0.

Or any of the methods that you have been taught, then post up your attempt.
Reply 2
Original post by L'art pour l'art
Is it an=3an12an2  (a1=a2=2)a_{n} = 3a_{n-1}-2a_{n-2} ~~ (a_{1} = a_{2} = 2)?

Consider the characteristic equation of the recurrence: 2x23x+1=0.2x^2-3x+1 = 0.

Or any of the methods that you have been taught, then post up your attempt.


Good advice in general but for this particular sequence an=2a_n=2. :tongue:

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