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C3 but slightly harder (Differentiation)

Could anyone please start me off with differentiating y= (sinx)^(sinx)??

What about y = x^x

Thanks!!
You could take logs of both side and differentiate implicitly ( ln(y) = xln(x), so 1/y * dy/dx = ..... ), or as an alternative method, note that y= x^x is the same as e^(ln(x^x)) = e^(xlnx) . Similar techniques will work for the sinx one :smile:

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