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C3 January 2013 25/01/2013

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Just for fun. Despite the fact that we can't tell :rolleyes:

Predictions anyone?
Sneaky feeling arcsin/cos stuff is going to come up.
Original post by posthumus
Sorry but for the previous question could you tell me what the range was ? :frown:

I still think its all real numbers.. I showed my brother the graph and he thinks so too.

So I'm really confused about -infinity thing


The range is all real numbers. :biggrin:
Original post by dan94adibi
The range is all real numbers. :biggrin:


the solomon made a mistake on one of the question http://www.school-portal.co.uk/GroupDownloadFile.asp?GroupId=1152244&ResourceId=3992029

question 6)a) http://www.school-portal.co.uk/GroupDownloadFile.asp?GroupId=1152244&ResourceId=3992017 mark scheme

they forgot for sin2A= to put the 2 in front of sinxcosx if u look
Reply 1764
Original post by AS01
:biggrin:
yes u do g-1g(x) but what is the answer?

its just x
Original post by This Excellency
Just for fun. Despite the fact that we can't tell :rolleyes:

Predictions anyone?


One of those lovely "Express dy/dx in terms of x" things, where you have to do dx/dy first :colone:

Arcsin/cos/tan is always a suspect because it hardly comes up... but it probably won't come up this time either :lol:

Hope the logs/exponentials questions aren't too tricky...
that trig question is such a basted on the june 2012 paper
Original post by posthumus
Enjoy !


Thanks Mate.
Original post by ThatRandomGuy
Sneaky
feeling arcsin/cos stuff is going to come up.


Yeah, that would be sneaky of them :colone: Prepare for everything :tongue:

So how comes you didn't revise for this?


Original post by suncake
One of those lovely
"Express dy/dx in terms of x" things, where you
have to do dx/dy first :colone:

Arcsin/cos/tan is always a suspect because it
hardly comes up... but it probably won't come up
this time either :lol:

Hope the logs/exponentials questions aren't too
tricky...


That would be nice :colone: :tongue:

June 2007 had a ugly log question that I just about managed to kill off :redface:

I'm just excited to finish C3 so we can start C4 and M2 :dance:
Reply 1769
some form of trig graphs my best guess for this exam
Original post by franzk
some form of trig graphs my best guess for this exam


What do you think this trig graph question would be like ? :smile:


EDIT: Oh right I see what you mean... a question involving arcsin & the inverse graphs. Yup thats quite likely :smile:
Tips for tomorrow - ALWAYS check your answers by plugging things back into the original equation (especially on trig). And don't take any short cuts write out ALL working in full! (I've made silly errors on other modules before which cost me a whole grade).

Anyway good luck everyone hope this exam doesn't whip us too hard! (I know that didn't really make sense but I can't think of some clever analogy right now) :tongue:
Original post by This Excellency
That would be nice :colone: :tongue:

June 2007 had a ugly log question that I just about managed to kill off :redface:

I'm just excited to finish C3 so we can start C4 and M2 :dance:


Just looked it up, and yes, that question was just.. eww. :tongue:

C4 is pretty nice in comparison to C3! Never done mechanics but it seems interesting :smile:


I've basically spent the past hour faffing around with my new hat, instead of doing any revision... Gonna blast through another past paper, then bed time for me. Good luck for tomorrow, everyone! :h:
Original post by suncake
Just looked it up,
and yes, that question was just.. eww.
C4 is pretty nice in comparison to C3! Never done
mechanics but it seems interesting

I've basically spent the past hour faffing around
with my new hat, instead of doing any revision...
Gonna blast through another past paper, then
bed time for me. Good luck for tomorrow,
everyone! :h:


I hope so! My teacher reckons it's easier than C3 but then again, he teaches maths for a reason. :rolleyes:

New hat :colone: Pimp hat? Rap star hat? Top hat?
I wish I could wear hats. I just look weird :tongue:

Haven't been doing any work either. I'm just watching Southland :tongue: We still have all of tomorrow morning to do some last minute prep.

Good luck to you too :h:

You going for the A*?
Original post by suncake
Just looked it up, and yes, that question was just.. eww. :tongue:

C4 is pretty nice in comparison to C3! Never done mechanics but it seems interesting :smile:


I've basically spent the past hour faffing around with my new hat, instead of doing any revision... Gonna blast through another past paper, then bed time for me. Good luck for tomorrow, everyone! :h:


That's a relief! :tongue: C3 isn't exactly hard, it's just annoying.



how would you do this someone!!! what values would you put into tan(a+b)
How do you differentiate these:
Sec kx
Cot kx
Cosec kx

is it:
ksec(kx)tan(kx)
-kcosec^2(kx)
-kcosec(kx)cot(kx)

(They're not on data sheet with k, only tankx is)

I have a question with y=e^(2x) sec(3x) and need to find dy/dx and not sure what to do for sec.
I know I can just make it e^(2x) / cos(3x) and use the quotient rule but I would rather learn this way ^^
Reply 1777
Original post by MyNameIsRay
How do you differentiate these:
Sec kx
Cot kx
Cosec kx

is it:
ksec(kx)tan(kx)
-kcosec^2(kx)
-kcosec(kx)cot(kx)

(They're not on data sheet with k, only tankx is)

I have a question with y=e^(2x) sec(3x) and need to find dy/dx and not sure what to do for sec.
I know I can just make it e^(2x) / cos(3x) and use the quotient rule but I would rather learn this way ^^

If y=e2xsec(3x)y=e^{2x}sec(3x); dydx=2e2xsec(3x)+3tan(3x)sec(3x)e2x=e2xsec(3x)(2+3tan(3x))\frac{dy}{dx}=2e^{2x}sec(3x)+3tan(3x)sec(3x)e^{2x}=e^{2x}sec(3x)(2+3tan(3x))
Reply 1778
Has anyone been taught how to do the half angle questions? Do we need to know that for our exams? I'm really starting to panic now :erm:
Original post by MyNameIsRay
How do you differentiate these:
Sec kx
Cot kx
Cosec kx

is it:
ksec(kx)tan(kx)
-kcosec^2(kx)
-kcosec(kx)cot(kx)

(They're not on data sheet with k, only tankx is)

I have a question with y=e^(2x) sec(3x) and need to find dy/dx and not sure what to do for sec.
I know I can just make it e^(2x) / cos(3x) and use the quotient rule but I would rather learn this way ^^


for cot(kx)

y=[tan(kx)]^-1

dy/dx = -k[sec^2(kx)]^-2

???? :confused:

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