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Differentiation help

how to differentiate y = 5e^(2x-sin(x^2)) man I'm stuck which method to use?

SOLVED
(edited 11 years ago)
Original post by hihihihihi
how to differentiate y = 5e^(2x-sinx^2) man I'm stuck which method to use?

Chain rule.

If it helps, let u=2x−sin⁡(x2)u=2x - \sin (x^2) [or 2x−sin⁡2x2x-\sin ^2 x, depending on what you're actually differentiating (it's hard to tell without the brackets!)] and recall that dydx=dydu×dudx\dfrac{dy}{dx} = \dfrac{dy}{du}\times \dfrac{du}{dx}.
(edited 11 years ago)
Chain rule that bad boy
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hihihihihi
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18
TY guys I got it dy/dx = 5 (2-2xcos(x^2))e^(2x-sin(x^2))

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