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Torque and angular acceleration/veolcity

Hello,

Question:



I know that τ=Iα\tau = I\alpha, τ\tau = Weight x distance from pivot to centre of mass and I=mR2+mR2+mR2I = mR^2 + mR^2 + mR^2.

So 6mg×43b=23mb2×α6mg \times \frac{4}{3}b = 23mb^2 \times \alpha. From this equation I get value of α\alpha, but my problem is about finding angular velocity, ω\omega from α\alpha.

Although, α=ω−ω0t\alpha = \dfrac{\omega - \omega_0}{t}, but I don't know the value of t.

How do I find ω\omega? :s-smilie:

Any help would be appreciated.
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Avatar for teachercol
teachercol
9
Again easier to use loss in grav pe = gain in ke

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