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Inz differentiation of

If z is a constant is Inz a constant

Anyone?


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it's z multiplied by the variable you're integrating with respect to.

e.g. int z dx = zx + c

Wait you do mean ingrate z or do you mean ln(z)?
I suspect this is another case of mistaken identity for the natural logarithm.

The natural logarithm of a constant is indeed a constant (so long as the original constant is positive).
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davros
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Original post by cdoyle
If z is a constant is Inz a constant

Anyone?


This was posted from The Student Room's iPhone/iPad App


Is there some background to this question?

If z is a constant, then so is f(z) for any function f you may choose :smile:

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