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c3 june 2009 edexcel

how to solve e^x +3e^-x -=4
Original post by lopper
how to solve e^x +3e^-x -=4

Well this is your equation
Unparseable latex formula:

e^x +3e^-^x =4


This is the same as ex+3ex=4e^x + \dfrac{3}{e^x} =4
You have a disguised quadratic. You can now substitute ex for something else like y and then solvee^x \ for \ something \ else\ like \ y \ and \ then \ solve

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