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Hard redox

Tynos

KMnO4(aq) + H2S(aq) + H2SO4(aq) -> K2SO4(aq) + MnSO4(aq) + S(s)

Can someone help me balance this please?

Reply 1

Secret.

Original post by Tynos

KMnO4(aq) + H2S(aq) + H2SO4(aq) -> K2SO4(aq) + MnSO4(aq) + S(s)

Can someone help me balance this please?

What have you done so far?

Reply 2

Tynos

Original post by Secret.

What have you done so far?

Nothing i dont know how to approach it.

Reply 3

SheldonWannabe

Original post by Tynos

KMnO4(aq) + H2S(aq) + H2SO4(aq) -> K2SO4(aq) + MnSO4(aq) + S(s)

Can someone help me balance this please?

There's some things missing on the right hand side. Hydrogen seems to have gained the ability to vanish leaving no trace.

Reply 4

charco

Study Forum Helper

Original post by Tynos

KMnO4(aq) + H2S(aq) + H2SO4(aq) -> K2SO4(aq) + MnSO4(aq) + S(s)

Can someone help me balance this please?

You are clearly missing water molecules on the RHS.

What you need to do first is identify the two half equations for the reduction and the oxidation process. The manganate(VII) ion is a strong oxidising agent, so you are looking at the sulphur(-II) changing to sulphur.

Then you multiply each half equation to equalise the electrons.

Then you add the two half equations together and cancel out common terms ...