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Finding the temprature

If we have the volume of sample of nitrogen gas that equal to 0.080 m^3 in Standard atmosphere pressure 101 pa and there is 3.6 mol from the gas then what is the temperature of the gas

I think the law to use is :Pv=nRT .But I am not sure
Original post by MAA_96
If we have the volume of sample of nitrogen gas that equal to 0.080 m^3 in Standard atmosphere pressure 101 pa and there is 3.6 mol from the gas then what is the temperature of the gas

I think the law to use is :Pv=nRT .But I am not sure


Yep, that's the correct law (generally volume is a capital V).
Reply 2
Avatar for MAA_96
MAA_96
OP
Original post by PythianLegume
Yep, that's the correct law (generally volume is a capital V).

So I have p =101,V=0.80,n=3.6

And?
Reply 3
Avatar for Rhodopsin94
Rhodopsin94
Original post by MAA_96
So I have p =101,V=0.80,n=3.6

And?


Isn't the standard atmospheric pressure (approx.) 1.0 x 10^5 Pa?

In which case you would do:

pV = nRT

therefore:

T = pV/nR = (1.0 x 10^5 x 0.080)/(3.6 x 8.31)

Plug that into your calculator, and you should get a value for the temperature in kelvin.

(Btw you have given two different volumes, not sure which you meant but I used the first)


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Reply 4
Avatar for MAA_96
MAA_96
OP
Original post by Rhodopsin94
Isn't the standard atmospheric pressure (approx.) 1.0 x 10^5 Pa?

In which case you would do:

pV = nRT

therefore:

T = pV/nR = (1.0 x 10^5 x 0.080)/(3.6 x 8.31)

Plug that into your calculator, and you should get a value for the temperature in kelvin.

(Btw you have given two different volumes, not sure which you meant but I used the first)


Posted from TSR Mobile


Thank you and yes I meant the first volume

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