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Competition - post a photo you've taken of nature >>
Competition - post a photo you've taken of nature >>
Competition - post a photo you've taken of nature >>

projectile motion help

so could someone please help me out with that question, i have no idea where i went wrong yet my answers are different to those in the book!

Thanks


IMG_0701[1].jpg i ticked the first one but its 0.7m/s out so i think it may actually be wrong
(edited 10 years ago)
IMG_0700[1].jpg516.0KB
Original post by Davelittle
so could someone please help me out with that question, i have no idea where i went wrong yet my answers are different to those in the book!

Thanks


If you want us to show you where you went wrong you need to post your answers and working.
Reply 2
Avatar for Davelittle
Davelittle
OP
13
Original post by Stonebridge
If you want us to show you where you went wrong you need to post your answers and working.


sorry my bad, its on now
The 1st one is wrong.

The initial velocity is 4m/s as the balloon is descending.
So use u=4m/s not zero.
You should also state which equation you have used and not just an expression with numbers in it.
So for part 2 where did you get t = square root expression? from.

To do part two use the correct answer for v from part 1 and use v = u + gt to find t
Reply 4
Avatar for Davelittle
Davelittle
OP
13
Original post by Stonebridge
The 1st one is wrong.

The initial velocity is 4m/s as the balloon is descending.
So use u=4m/s not zero.
You should also state which equation you have used and not just an expression with numbers in it.
So for part 2 where did you get t = square root expression? from.

To do part two use the correct answer for v from part 1 and use v = u + gt to find t


IMG_0702[1].jpg

Thanks so much, i took the balloon as ascending for some reason :/

well t=root(2s/a) when u=0 so thats where its from!

once again thanks very much +rep!

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