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Official AQA AS Chemistry Unit 1 - 23Rd May 2013

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    Hi Everyone,

    Thought I'd create a thread for everyone to discuss about the chemistry exam this week.

    Any predictions, revision tips and help can be posted here!

    Good luck everyone!!
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    I'm gonna have my ion this thread... :teehee:
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    Wooooooooooooooooooooo
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    (Original post by The.Joker)
    I'm gonna have my ion this thread... :teehee:
    Smart. :ahee:
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    Anyone got any good notes on bonding? Any tips on how to easily identify which kind of forces are acting upon certain elements
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    (Original post by The.Joker)
    I'm gonna have my ion this thread... :teehee:
    I lol'ed.
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    Anybody got any ideas on key topics to come up?
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    Thing is, I forgot about this resit, I had two maths exams last week ( stats T.T ) and biol with another maths exam this week, and I know I haven't done enough revision for it..
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    (Original post by Manni)
    Anyone got any good notes on bonding? Any tips on how to easily identify which kind of forces are acting upon certain elements
    It's just non-metal-non-metal bond = Covalent
    Metal-non-metal = Ionic
    Metal-metal = Metallic

    Hydrogen bonds between H + (N,F,O) - Strongest IMF.
    Permanent dipole - I think it's C-Cl bonds and stuff...
    VDW - Weakest IMF.
    Hmm.
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    (Original post by buzzing22)
    Anybody got any ideas on key topics to come up?
    This
    +
    Since i'm new i thought I'll contribute;
    http://www.youtube.com/playlist?list...3yF3mJzSsts6Rl
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    (Original post by The.Joker)
    I'm gonna have my ion this thread... :teehee:

    Hahaha!!!
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    so I came across this question in Jan12 paper and I got a completely different answer from the markscheme on what the name of it is...
    the markscheme says it's called 2,2 dichloro 3 methyl pentane....i don't understand why, anyone wanna help me?
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    (Original post by buzzing22)
    Anybody got any ideas on key topics to come up?
    This + Since I'm new thought I'll contribute;
    http://www.youtube.com/playlist?list...3yF3mJzSsts6Rl
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    (Original post by tumblrgirl)
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    so I came across this question in Jan12 paper and I got a completely different answer from the markscheme on what the name of it is...
    the markscheme says it's called 2,2 dichloro 3 methyl pentane....i don't understand why, anyone wanna help me?
    Longest carbon chain is 5 so PENT
    No C=C so ANE
    2Chlorines on Carbon2 So 2,2 Dichloro
    1 Methyl group on Carbon 3 so 3 Methyl
    Add them together in alphabetical order 2,2-Dichloro-3-MethylPentane
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    (Original post by tumblrgirl)
    Click image for larger version. 

Name:	image.jpg 
Views:	1671 
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ID:	218014

    so I came across this question in Jan12 paper and I got a completely different answer from the markscheme on what the name of it is...
    the markscheme says it's called 2,2 dichloro 3 methyl pentane....i don't understand why, anyone wanna help me?
    It's pent- because the longest chain is five carbons (it's not straight it's goes 'round the corner' the CH3 group on the bottom right is carbon number 1 if you get me). The chlorines are both on the second carbon and then there is a methyl group on the third carbon.
    That's actually quite complicated when you look at it, I definitely wouldn't have got that answer :L
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    ooh thanks guys, i'm so silly, i didn't realise that there were 5 carbons -_-
    thanks again
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    If anybody has other exam questions they are stuck on, feel free to post, Would benefit yourself and everyone else
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    this sounds really stupid but how do you know which carbon you would say is carbon 1, etc?
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    watchin, done no revision so far, im doing c2 at the moment
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    (Original post by tumblrgirl)
    this sounds really stupid but how do you know which carbon you would say is carbon 1, etc?
    Take this for example
    You would deduce which way you look at it gives you the smallest number on the carbon chain, from left to right it would be 4,4-DiChloro-3-MethylPentane. You then would look at it from the other way (right to left) and it would be 2,2-DiChloro-3-MethylPentane.
    As you can see the position of the functional groups on the 2nd Haloalkane is lower than the 1st Haloalkane so that would be it.
    Hope this makes sense.

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