Edexcel S4 21st June 2013

Yeah I've not done much on it yet. There's so little on the syllabus for it that the questions are all so similar anyway. Are you doing Further-Additional maths then, if you're doing M4 and M5?

What days the exam? I just did S3 and i didn't enter for S4 cos i wasn't sure whether i was ready for it - now regretting that!

I've done:

C1, C2, FP1, S1, S2, S3, D1, D2

So I'm a module behind for AS further maths additional :/

Yep. Now done D2, M3 and S3 - just got M4, S4 and M5 to go now, then I'll have done the lot.

So are you doing the additional FM AS, or just a lot of stats for your further?

Guys can you explain this question on the June 11 paper? I've never seen the notation before... question 6a.

http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/June%202011%20-%20QP/6686_01_que_20110623.pdf

Oh, I remember that question. Do you mean you don't recognise the form of f(y)? Think (or look) back to S2 continuous random variables. It's just saying that for y values 0 to beta the value of f(y) is the thing to left of that, and for all other values of y f(y)=0.

Remember also that

$E(Y)=\int yf(y)dy$

Over the range of y, in this case 0 to beta.

If you require any other help, please do ask!

Does that translate to $E(Y^m)=\int y^mf(y)dy$?

I remember continuous random variables, its the $max {(X_1, X_2.., X_n)}$ I don't recognise...

Yes, that's right.


Oh, that just means the maximum value of the values in brackets, for example:

MAX(1, 5, 8, 2, -3, 7) = 8

What days the exam? I just did S3 and i didn't enter for S4 cos i wasn't sure whether i was ready for it - now regretting that!

I've done:

C1, C2, FP1, S1, S2, S3, D1, D2

So I'm a module behind for AS further maths additional :/

What do you guys do for AS further maths additional?

I'm doing 15 modules but it's unclear exactly what will count towards what...

C1 - 4
M1 - 3
S1 - 4
D1
and FP1 - 3

What do you guys do for AS further maths additional?

Quick question. In the book (page 25, part c) It asks to find a consistent estimator for the function.

Would really appreciate any help, as I really can't get myead around this part of the chapter at all.

Parts (a) and (b) of this example are contents from S2. Also stuff from S1 like the E(X) and Var(X) for continuous uniform distribution will creep up. It would be wise to look through those chapters if they're causing you problems.

$E(M)= \frac{na}{n+1}$ is the answer from part (a) as you should have calculated.

so $(n+1)E(M)=na$ and $\frac{(n+1)E(M)}{n}=a$

Let M=E(M), so $E(Q)= \frac{(n+1)M}{n}=a$

Find the variance of Var(Q) by taking out $\frac{n+1}{n}$ and square it because you're doing variance, and substitute the answer for Var(M) in part (b). You now get the varience for estimator Q.

The definition of consistent estimator is that when n gets larger, the varience of the estimator gets smaller. Check if Var(Q) does that. If Var(Q) does, then Q is a consistent estimator of a.