The Student Room Group

largest interval on which f(z) continuous?

Hi,

just wanted to check:

Qn: find the largest region in the complex plain on which f(z)=Re(z)Im(z)f(z)=Re(z)Im(z) is continous?

i get the entire complex plane excluding z=0.

(since f(z)=w=xyf(z)=w=xy) (akin to this in catesian co-ordinates is the hyperbolic parabola)

book sais entire complex plane?
(edited 10 years ago)
Reply 1
If the function isn't continuous at z=0 then show me a path from a general point z=x + iy to z=0 which isn't continuous.
Reply 2
you can approach (0,0) from 4 different directions, all of which end up having a limit of 0 (+/- xreal/imaginary axis.)
Reply 3
Original post by Hasufel
you can approach (0,0) from 4 different directions, all of which end up having a limit of 0 (+/- xreal/imaginary axis.)


You can approach z=0 in infinitely many different directions and ways - not just 4. You ave to show that it is continuous for every single direction and way.

Try f(z) = xy/(x^2+y^2) - this isn't continuous as the results differ as you approach (0,0) along the lines x=0 and x=y.
Reply 4
Proof that the given function is continuous at z=0z = 0:

Spoiler



The proof that this holds for any zCz \in \mathbb{C} is a simple extension of the above, and is left as an exercise.
(edited 10 years ago)

Quick Reply

Latest