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A2 Equlibria q

CO + 2H2 <=> CH3OH

At the start:
CO: 0.240mol
H2: 0.380mol

At equilibrium
CO: 0.170mol
H2: (calculate)
CH3OH: (calculate)

I don't understand. There's 0.240mol CO, 0.170 is left, so 0.07 has gone to methanol. Am I right in saying there is 0.240mol hydrogen too? Since there is a 1:2 ratio between CO and hydrogen.

Answers: moles of methanol at equilibrium = 0.07
moles of hydrogen = 0.240 (HOW?)
(edited 10 years ago)
Original post by Magenta96
CO + 2H2 <=> CH3OH

At the start:
CO: 0.240mol
H2: 0.380mol

At equilibrium
CO: 0.170mol
H2: (calculate)
CH3OH: (calculate)

I don't understand. There's 0.240mol CO, 0.170 is left, so 0.07 has gone to methanol. Am I right in saying there is 0.240mol hydrogen too? Since there is a 1:2 ratio between CO and hydrogen.

Answers: moles of methanol at equilibrium = 0.07
moles of hydrogen = 0.240 (HOW?)


Yep, you're correct.

There are 0.240 moles of hydrogen because of the 1:2 molar ratio in the equation. You've calculated that 0.07 moles of CO reacted, so double this (0.14) of hydrogen must have reacted. 0.38-0.14=0.24
Reply 2
Avatar for Magenta96
Magenta96
OP
16
Original post by PythianLegume
Yep, you're correct.

There are 0.240 moles of hydrogen because of the 1:2 molar ratio in the equation. You've calculated that 0.07 moles of CO reacted, so double this (0.14) of hydrogen must have reacted. 0.38-0.14=0.24


Thank you, but since 0.14 moles of hydrogen have reacted, why aren't they added to methanol's moles? So it'd be like:
CO moles: 0.170
H2 moles: 0.240
CH3OH moles: (0.07 + 0.14)
(edited 10 years ago)
Original post by Magenta96
Thank you, but since 0.14 moles of hydrogen have reacted, why aren't they added to methanol's moles? So it'd be like:
CO moles: 0.170
H2 moles: 0.240
CH3OH moles: (0.07 + 0.14)


You need to look at the molar ratios in the equation. CO is 1, H2 is 2 and CH3OH is also 1. This means that the same number of moles of methanol are produced as carbon monoxide reacts.
Reply 4
Avatar for Magenta96
Magenta96
OP
16
Original post by PythianLegume
You need to look at the molar ratios in the equation. CO is 1, H2 is 2 and CH3OH is also 1. This means that the same number of moles of methanol are produced as carbon monoxide reacts.


okay, thank you :smile:

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