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alisa
What's oxalate? I think I did it wrong, don't worry. I realised i'd left it out right at the end and just saw something that looked like 'en'(it had lots of CH2's and N's :confused: ), so I tried to draw it quickly. It was very rushed so probably wrong.


oxalate = ethandioate
someone tell me i havent done it wrong pleaseeeeeeeee lol i need as many marks as i can get!
Reply 21
i thought that was one of the worst chm5 papers! i went thru all the past papers, n they did have some difficult questions, but 2days papers was much harder. i think the only good part was the mechanisms in section B..
as for chm6.. jus a typical multiple choice paper.. some tricky stuff, but not alot different from past papers..
well jus gota hope for the best now!
Reply 22

Module 5 was okay, they had many organic questions which made it simple. The only thing I forgot how to do is the partial pressure question, the calculation bit. I couldnt find the parial pressures of the 2 so couldnt do the calculations. So lose 4 marks there.

I am a bit annoyed that they didn't ever since ask any colour changes.

The synoptic paper was hard, maybe because I didnt really revised it. Its so easy to lose marks on it so the only result I am worried about is synoptic...
Reply 23
was it aluminium hydroxide? lol

woops, i put AL2CO3+6HCL=2ALCL3+3HCL
Reply 24
Can anyone remember what they got for the partial pressures and the % of Fe question?
Reply 25
I think I got 96.1% if I remember for the iron, couldnt get the parial pressure...
Reply 26
I ended up with 4MPa and 12MPa for partial pressures. I think I got the % of Fe wrong.
Reply 27
I get 4 and 12 for the PPs, and 96.1% rings a bell.
Reply 28
Damn I wonder where I went wrong on that!


Edit - Actually now I think of it, I may have gotten an answer like that, I remember thinking it was a big percentage. I wish I could remember what I put now.
Reply 29
wooohoo, that's wht i got :biggrin::biggrin: happy chappy
Reply 30
I loved the autocatalysis question in section B with Mn2+/Mn3+ I was hoping that would come up.
Reply 31
I did Al(OH)3 + NaOH --> NaAl(OH)4 and
Al(OH)3 + 3 HCL --> AlCl3 + 3H2O

First shows it can act as a acid, second as a base

Did anyone think there was a mistake in section B of module 5? It asked to show mechanism of Chlorine reacting with an alkane to form an haloalkane. Surely it meant alkene? Didn't work to that assumption though, so I guess I lost those 3 marks.

I though module 6 was pretty easy, only 2-3 tough questions I found.
Reply 32
Oh and for the structure of the Chromium thing, I'm fairly certain it was a Cr3+ surrounded by 3 of whatever diamine it was, with the lone pair on the N being donated- which answers the next question of why is the enthalpy change approx. 0- its because the same number and type of bonds are being broken and formed (both N:->Cr3+).

EDIT:
Pav27


Did anyone think there was a mistake in section B of module 5? It asked to show mechanism of Chlorine reacting with an alkane to form an haloalkene. Surely it meant alkene?


No, I don't think so, the mechanism is Free Radical Substition (you need UV light to do it).
Reply 33
Kernel
No, I don't think so, the mechanism is Free Radical Substition (you need UV light to do it).


Oh, *******s.
Reply 34
Pav27
I did Al(OH)3 + NaOH --> NaAl(OH)4 and
Al(OH)3 + 3 HCL --> AlCl3 + 3H2O

First shows it can act as a acid, second as a base

Did anyone think there was a mistake in section B of module 5? It asked to show mechanism of Chlorine reacting with an alkane to form an haloalkane. Surely it meant alkene? Didn't work to that assumption though, so I guess I lost those 3 marks.

I though module 6 was pretty easy, only 2-3 tough questions I found.


lmao, exactly wht i thought, until my friend told me otherwise, 3 marks though

kes
Reply 35
I did the free rad substitution thing, did you just have to write the equations?

i.e. Cl2 ----> 2Cl*

CH4 + Cl* ---> CH3* + HCl

CH3* + Cl* ----> CH3Cl
Reply 36
Pav27
I did Al(OH)3 + NaOH --> NaAl(OH)4 and
Al(OH)3 + 3 HCL --> AlCl3 + 3H2O

First shows it can act as a acid, second as a base

Did anyone think there was a mistake in section B of module 5? It asked to show mechanism of Chlorine reacting with an alkane to form an haloalkane. Surely it meant alkene? Didn't work to that assumption though, so I guess I lost those 3 marks.

I though module 6 was pretty easy, only 2-3 tough questions I found.


I did free radicals reaction, where cl2 is split to cl* and that reacts with ch4 to form ch3*
where ch3* react witth cl* to form ch3cl an haloalkane

i also thought they got it wrong, but i thought about it :smile:
Reply 37
Yeh...I found the partial pressures one really hard...and I am sure they are usually easy!! I ended up with 4 and 12MPa for the partial pressures...does that sound right??

For the amphoteric aluminium hydroxide I put ---> [AL(OH)4]^1- but I couldnt think of the acid reaction......was it ---> AlCl3


Also it was a right of sun of a b*tch to draw that Cr with the 3 bidentate amine ligands! What did everyone put for the organic products with the Cr2O7^2-?.....I put a carboxylic acid for the reflux one and an aldehyde for the other.
Reply 38
rustynator
Yeh...I found the partial pressures one really hard...and I am sure they are usually easy!! I ended up with 4 and 12MPa for the partial pressures...does that sound right??

For the amphoteric alumin hydroxide I put ---> AL(OH)4]^1- but I couldnt think of the acid reaction......was it -----> AlCl3


Also it was a right of sun of a b*tch to draw that Cr with the 3 bidentate amine ligands! What did everyone put for the organic products with the Cr2O7^2-.....I put a carboxylic acid for the reflux one and an aldehyde for the other.


I put the same as you for everything I think. Was the bidentate ligand 'en', NH2CH2CH2NH2. I didn't read the question properly.
Reply 39

yeah, it was, the N atoms donate their lone pairs to the cr3+. Increase entropy... chelate effect... from h20 to ethane-1,2- diamine

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