That would mean that the P(1R and 1B) is zero - do you think that is so?
i'm having a brain freeze moment. How would that mean it's zero? Ugh it's so annoying I always find I can do all the 'harder' maths stuff but then simple things trip me up :/
i'm having a brain freeze moment. How would that mean it's zero? Ugh it's so annoying I always find I can do all the 'harder' maths stuff but then simple things trip me up :/
You have the following possibilities for your 4 cards
RRRR RRRB RRBB RBBB BBBB
Since you can turn over 2 black, the first 2 can be ignored Since the P(2B) is not 1 we can ignore the latter
So we have
RRBB or RBBB
For each of these work out the P(2B) use a tree diagram maybe?
i'm having a brain freeze moment. How would that mean it's zero? Ugh it's so annoying I always find I can do all the 'harder' maths stuff but then simple things trip me up :/
If you're saying the probability of both 2 black cards is 0.5 and the probability of 2 red cards is also 0.5, then those are the only two possibilities.
Meaning that you believe that when turning over 2 random cards the probability of them being of different colours is 0.