You might have been told, that phenol is a weak acid, while ethanol is not. Both have the -OH group, but somehow the O-H bond in phenol may be broken easier and that's why it has acidic character. Why is that? Of course, because the group in phenol is connected to the aromatic ring. The ring influences in the following way: Lone pair of the oxygen is attracted to the ring. This way the ring gains a negative charge near the bond with oxygen, and oxygen gains a positive charge. The negative charge is then 'moving' around to finally get to its initial position. This process is going over and over (see attached photo). This way the bond O-H is weaker, because the electron density is 'pulled' toward the aromatic ring. Notice, that is actually why -OH group activated positions ortho- and para-.
Answering the question: The donation is not a part of aromaticity, but it's a result of oxygen being attached to aromatic ring (An oxygen atom alone cannot be attached, as it would need a double bond.)
See the photo, blue arrows show electrons' movement while the green arrows show different forms (these are called resonance structures)
EDIT: As you can see, the photo shows creating a double bond. This indicates that pi electrons of the oxygen become delocalized just as the electrones of the ring.
Just to finish about the acidity: Of course if oxygen loses the electron density from the side of aromatic ring, it pulls the electrons of the -OH bond. Thus, the bond is broken easier.
I'm actually not an undergraduate student. I'm still in high school, so I might have said something wrong. Sorry for the possible inconvenience.