The Student Room Group

ester hydrolysis with NaOH

please see attached
Original post by TheGreaterGood
please see attached


Lose the water molecule from each side ...
Original post by charco
Lose the water molecule from each side ...


why would you do that though

because it is a hydrolysis (using water to break down a compound) so don't you need the water?:dontknow:
Original post by TheGreaterGood
why would you do that though

because it is a hydrolysis (using water to break down a compound) so don't you need the water?:dontknow:


If you use aqueous sodium hydroxide you don't need to use water in the equation. The reagent is the aqueous hydroxide ion. The chemical equation shows only that which reacts and is formed.

RCOOR' + NaOH --> RCOONa + R'OH
Just like in mathematical equations, if something is on both sides of an equation, it just cancels (x + 6 = y + 6 which is just x = y).

Also, when drawing sodium ethanoate it's best not to draw the sodium attached to the oxygen with a covalent bond (-O-Na) - it's ionic :smile:
Original post by EierVonSatan
Just like in mathematical equations, if something is on both sides of an equation, it just cancels (x + 6 = y + 6 which is just x = y).

Also, when drawing sodium ethanoate it's best not to draw the sodium attached to the oxygen with a covalent bond (-O-Na) - it's ionic :smile:


that makes sense :thumbsup:
Thanks for pointing that out :biggrin:

Original post by charco
If you use aqueous sodium hydroxide you don't need to use water in the equation. The reagent is the aqueous hydroxide ion. The chemical equation shows only that which reacts and is formed.

RCOOR' + NaOH --> RCOONa + R'OH


Ohhh. Thhanks :dance:

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