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help needed maths

can someone please solve this for x thanks a lot:biggrin:
ln(x+2)-ln(x+1)=1
Reply 1
Avatar for Nitrogen
Nitrogen
16
Original post by kiyubi
can someone please solve this for x thanks a lot:biggrin:
ln(x+2)-ln(x+1)=1

^ solutions
Reply 2
Avatar for kiyubi
kiyubi
OP
9
Original post by Nitrogen
^ solutions


oh yh, thanks a lot!:biggrin:yr great i appreciate it:biggrin:
Reply 3
Avatar for kiyubi
kiyubi
OP
9
Original post by Nitrogen
^ solutions


THANKS A LOT!
could you help me with these three as well ive tried thousand times nd i dont seem to be getting the right answer
thank you
differentiate
y=sin(root 3x+1)
y=(ln(root x))^2
y=e^root 6x

thanks again
Reply 4
Avatar for Liamnut
Liamnut
13
Original post by kiyubi
THANKS A LOT!
could you help me with these three as well ive tried thousand times nd i dont seem to be getting the right answer
thank you
differentiate
y=sin(root 3x+1)
y=(ln(root x))^2
y=e^root 6x

thanks again


Are you familiar with the chain rule? All of these questions can be completed using it along with standard results. The second one can be done using the product rule as well as the chain rule.

Having people do the questions for you really won't help.
(edited 10 years ago)
Reply 5
Avatar for TenOfThem
TenOfThem
18
Original post by HelpTheInnocent
....



Original post by Nitrogen

...


The forum guidelines

http://www.thestudentroom.co.uk/showthread.php?t=403989

Ask that we give guidance rather than full solutions
Reply 6
Avatar for kiyubi
kiyubi
OP
9
Original post by Liamnut
Are you familiar with the chain rule? All of these questions can be completed using it along with standard results. The second one can be done using the product rule as well as the chain rule.

Having people do the questions for you really won't help.


iam not trying to get the answers, ive already got answers, i know you have to use chain rule, but i keep getting it wrong, theyre all the same am just trying to understand where am going wrong, nd i dont cheat if thats what you mean, because i got an A in my AS maths last year i dont need cheating nd i know it wont help
Original post by kiyubi
iam not trying to get the answers, ive already got answers, i know you have to use chain rule, but i keep getting it wrong, theyre all the same am just trying to understand where am going wrong, nd i dont cheat if thats what you mean, because i got an A in my AS maths last year i dont need cheating nd i know it wont help


Then you need to start showing *your* working.
Reply 8
Avatar for kiyubi
kiyubi
OP
9
Original post by Mr M
Then you need to start showing *your* working.


heres my working
WP_002046.jpg310.2KB
WP_002047.jpg302.2KB
Original post by kiyubi
heres my working


You are making the wrong substitution.

u=(3x+1)12u=(3x+1)^{\frac{1}{2}} for the first one.
On the second one note that (ln⁡x)2=(12ln⁡x)2(\ln \sqrt x)^2 = (\frac{1}{2} \ln x)^2

The substitution should be u=12ln⁡xu=\frac{1}{2}\ln x
Reply 11
Avatar for kiyubi
kiyubi
OP
9
Original post by Mr M
On the second one note that (ln⁡x)2=(12ln⁡x)2(\ln \sqrt x)^2 = (\frac{1}{2} \ln x)^2

The substitution should be u=12ln⁡xu=\frac{1}{2}\ln x

thanks a lot i appreciate it:biggrin:
(edited 10 years ago)

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