the integration of (2x+a)^3 is equals to 90 with the limits a and 0. I need to find what a is.
I integrated the function and got (2x+a)^4/8 and the limits are a and 0. Substituted a and 0 into the integral giving ((3a)^4/8)-(a/8) = 90 then multiplied 3a by power of 4 giving : (81a^4 / 8) - (a/8) = 90 brang the 8 to the other side giving: 81a^4-a=720 I then tried 2 solving for a numerous of ways and they all leaded me to the wrong answer so Im pretty sure something went wrong already... so how would i find a?
the integration of (2x+a)^3 is equals to 90 with the limits a and 0. I need to find what a is.
I integrated the function and got (2x+a)^4/8 and the limits are a and 0. Substituted a and 0 into the integral giving ((3a)^4/8)-(a/8) = 90 then multiplied 3a by power of 4 giving : (81a^4 / 8) - (a/8) = 90 brang the 8 to the other side giving: 81a^4-a=720 I then tried 2 solving for a numerous of ways and they all leaded me to the wrong answer so Im pretty sure something went wrong already... so how would i find a?
Well in the book it does say sqrt3 but the question didnt specifiy on how they want the answer to be written. If this was an exam would I loose a mark for writing 9^1/4 rather than sqrt3?