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Help with this rearrangement please

dD/(m - DQ) = dt/V - Equation 1

dD/(m/Q-D) = (Q/V)dt - Equation 2

Can someone explain what happens to make Equation 1 become Equation 2 ? I'm sure it's something simple but I can seem to figure it out.

I've tried multiply both sides of Equation 1 by Q but i cant see how it forms the left hand side of Equation 2...

Thanks
Original post by Voltozonic
dD/(m - DQ) = dt/V - Equation 1

dD/(m/Q-D) = (Q/V)dt - Equation 2

Can someone explain what happens to make Equation 1 become Equation 2 ? I'm sure it's something simple but I can seem to figure it out.

I've tried multiply both sides of Equation 1 by Q but i cant see how it forms the left hand side of Equation 2...

Thanks


Does this help?

dDm−DQ=dtV  ⟹  dDQ(mQ−D)=dtV\dfrac{dD}{m - DQ} = \dfrac{dt}{V} \implies \dfrac{dD}{Q \left( \frac{m}{Q} - D \right)} = \dfrac{dt}{V}
Original post by Voltozonic
It does indeed, thank you very much.

I was looking at it as m/(Q-D).


That would definitely make things more difficult! No problem :wink:

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