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How do SnI4/SnCl4 react with ethanol/toluene/HCl/NaOH?

Hi guys,

Having trouble with my lab where I have to figure out the reactions for both SnI4 and SnCl4 with ethanol, toluene, dil.HCl, conc.HCl and NaOH.

Could someone help me with the equations? I've taken a stab at a couple of them, but I'm just not too sure.

(So far I've got:
SnI4_(s) + CH₃CH₂OH_(aq) → Sn(OH)_4(aq) + 4CH₃CH₂I(aq)
SnI_4(s) + 4NaOH_(aq) → Sn(OH)_4(aq) + 4NaI_(aq)
SnCl_4(s) + 4NaOH_(aq) → Sn(OH)_4(aq) + 4NaCl_(s)
Are these okay?)

Thanks c:

Reply 1

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