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Maths C4 question help

Right I've only just started this topic so sorry if I'm missing something really obvious here.

Find the turning point of the curve x=t, y= t^2 -1

ive firstly subbed in x for where t is (this probsbly doesn't make any difference) y= x^2 -1

dy/dx = 2x

Now what?

Thanks for any help
Reply 1
Original post by RSmith1007
Right I've only just started this topic so sorry if I'm missing something really obvious here.

Find the turning point of the curve x=t, y= t^2 -1

ive firstly subbed in x for where t is (this probsbly doesn't make any difference) y= x^2 -1

dy/dx = 2x

Now what?

Thanks for any help


as with any turning point set the differential = 0
Reply 2
Original post by TenOfThem
as with any turning point set the differential = 0

But then y=-1 which is not whats in the answer book

thanks for your reply btw.
Reply 3
Original post by RSmith1007
But then y=-1 which is not whats in the answer book

thanks for your reply btw.


then the answer book is incorrect
Reply 4
(1/2, -3/4) is the answer
Reply 5
Original post by TenOfThem
then the answer book is incorrect

Hmm ok, is there not some sort of different process for this due to this topic being about parametric and Cartesian equation. If not then you must be right.
Reply 6
Original post by RSmith1007
(1/2, -3/4) is the answer


Not to the question in the OP it isn't
Reply 7
Original post by RSmith1007
Hmm ok, is there not some sort of different process for this due to this topic being about parametric and Cartesian equation. If not then you must be right.


There is certainly more than one approach but they all give the same answer (0,-1)
Reply 8
Original post by TenOfThem
There is certainly more than one approach but they all give the same answer (0,-1)

Ok thanks for the help

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