C4 integration
Can anyone explain to me why the integral of b) :
Is this:
Confused as to how to get there. Any help would be much appreciated!
Posted from TSR Mobile
Is this:
Confused as to how to get there. Any help would be much appreciated!
Posted from TSR Mobile
*int* 1/(2x+1)^2
Identical to
(2x+1)^-2
Add one to power
(2x+1)^-1
Now if you differentiated that you'd have -2 extra so divide by that -2
-1/2 (2x+1)^-1
Remember to add constant
And simplify
Identical to
(2x+1)^-2
Add one to power
(2x+1)^-1
Now if you differentiated that you'd have -2 extra so divide by that -2
-1/2 (2x+1)^-1
Remember to add constant
And simplify
What about ln?
EDIT: Nevermind those are for equations that aren't squared or greater.
EDIT: Nevermind those are for equations that aren't squared or greater.
Original post by ModernScholar
What about ln?
What about it?
Because it's 1/(ax+b)^n
If n is 2 or bigger, you'd use inverse chain rule, ln would be a looong route
Original post by Dilzo999
They changed it into index form so it would be and now you'd apply the inverse chain rule.
Ohhh yeah, can't believe I didn't spot that. Thanks!
Posted from TSR Mobile
Original post by L'Evil Fish
What about it?
Because it's 1/(ax+b)^n
If n is 2 or bigger, you'd use inverse chain rule, ln would be a looong route
Because it's 1/(ax+b)^n
If n is 2 or bigger, you'd use inverse chain rule, ln would be a looong route
I know, I worked it out a few moments later and edited my post.
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