Year 12s: what will be the first way you research your future options? >>

M2 Problem

A boy standing on a garage roof throws a ball horizontally with a speed 15m/s. The ball just clears a wall 1.5m high 10m away. Calculate height of projection.

maths 2.png

If it just clears the wall, the velocity at that point, the angle to the horizontal and vertical must be 45?

Am i right?

thanks!

(edited 10 years ago)

Reply 1

user2020user

Original post by Zenarthra

...

You can't just assume the angle of depression of the ball at the point of clearing the wall is

45^{\circ}

.
What you do know, is that the horizontal component velocity

v\cos \theta

is equal to 15m/s and remains constant whilst the ball is airbourne.
You can work out the vertical component of the velocity

v\sin \theta

by using the 'suvat' (or 'vatus' as a dear friend likes to call them) equations of motion.

(edited 10 years ago)

Reply 2

Wesbian

What was your working out for that?

Posted from TSR Mobile

Quick Reply

Latest

Articles for you

Btec results day 2024: what to expect

What is an LLM and how could it benefit your career?

Powerful questions business students forget to ask their career advisers

Why I chose a law degree and what studying law was like

M2 Problem

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you