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need these proofs .( level bachelors)

kindly post these proofs
1.grad(F.G) = F(curlG) + G(curlF) + (F.grad)G + (G.grad)F
2.grade . ((r cross a) cross b)= -2B.A
in que2 r,A,B ARE VECTORS
Original post by tweety1991
kindly post these proofs
1.grad(F.G) = F(curlG) + G(curlF) + (F.grad)G + (G.grad)F
2.grade . ((r cross a) cross b)= -2B.A
in que2 r,A,B ARE VECTORS

Please refer to this.
Have you tried elsewhere? DrMaths, Stackexchange maths and similarly themed sites often have a host of proofs available.
Reply 2
no
Reply 3
Original post by tweety1991
no


Try them
Reply 4
give me links
There is something called Google in case you aren't aware.

Peace.
Reply 6
i know dear. i searched it from many sites but didnt found anywhere thats y asked for help......and i didnt ask merely you.............
Original post by WhiteGroupMaths
There is something called Google in case you aren't aware.

Peace.
Reply 7
Original post by tweety1991
i know dear. i searched it from many sites but didnt found anywhere thats y asked for help......and i didnt ask merely you.............


You didn't look properly then. It's a basic property of div, grad, curl:

http://math.stackexchange.com/questions/467924/vector-calculus-identities-using-differential-forms/501237#501237
Reply 8
thanks noble i got it.......
Reply 9
Original post by tweety1991
kindly post these proofs
1.grad(F.G) = F(curlG) + G(curlF) + (F.grad)G + (G.grad)F
2.grade . ((r cross a) cross b)= -2B.A
in que2 r,A,B ARE VECTORS

They're easily proved using suffix notation (and/or considering them componentwise).
Original post by tweety1991
i know dear. i searched it from many sites but didnt found anywhere thats y asked for help......and i didnt ask merely you.............


Oh yes I am SURE you did search high and low. Left and right too probably.

Peace.

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