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how to calculate partial pressures

A mixture of 50 mol of methanol and 50 mol of CO reaches equilibrium at a pressure of 32atm. At 175degrees, the equilibrium partial pressure of ethanoic acid is 22.2 atm

CH3OH(g) + CO(g) => CH3COOH(g)

calculate the partial pressures of methanol and CO at equilibrium..


Ok I am not too sure how to go about this.. help would be great :smile:
The sum of the partial pressures equals the total pressure. You are also told that there are equal amounts of methanol and carbon monoxide before the reaction and they react 1:1 with each other to form ethanoic acid.

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