A mixture of 50 mol of methanol and 50 mol of CO reaches equilibrium at a pressure of 32atm. At 175degrees, the equilibrium partial pressure of ethanoic acid is 22.2 atm
CH3OH(g) + CO(g) => CH3COOH(g)
calculate the partial pressures of methanol and CO at equilibrium..
Ok I am not too sure how to go about this.. help would be great
The sum of the partial pressures equals the total pressure. You are also told that there are equal amounts of methanol and carbon monoxide before the reaction and they react 1:1 with each other to form ethanoic acid.